The perimeter of a rectangle is calculated by adding the lengths of all its sides. In this case, the rectangle has a length of 7 meters and a width of 3 meters. To find the perimeter, you would add the lengths of all sides: 7m + 7m + 3m + 3m = 20 meters. Therefore, the perimeter of a rectangle with dimensions 7m x 3m is 20 meters.
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20 meters
The perimeter (distance around the outside) = length + width + length + width
P = 2L + 2W
2 (7) + 2 (3) = 14 + 6 = 20
also:
P = 2 (L + W)
2(7 + 3) = 20
66
3 x 7 sq m
16 metres.
This is not the question I was looking for.1Record the length and width of a square or rectangle. Substitute your measurements into the formula "length x width" to solve for area. For example, a rectangle with a length of 7 meters (m) and a width of 3m has an area of: 7m x 3m = 21m^2 (21 meters squared, or 21 square meters).2Use the formula "(base x height)/2" to find the area of a triangle. A triangle with a height of 7m and a base of 3m has an area of 7m x 3m = 21m^2, divided by two equals 10.5m^2.
well if you add it it is easy. A:11m.The above is a load of bovine droppings. P = 2(L + W) so the CORRECT answer is 22 m.The perimeter of a rectangle is 2 x (length + width).2 x (7m + 4m) = 2 x 11m = 22m