28 meters
It would be a square because A = L x W so 49 = 7 x W and the width is 7.
Its perimeter is 4*7 = 28 meters.
The perimeter actually doesn't tell you anything about the breakdown betweenthe length and width. All we can tell about this one is that the sum of (length+width)has to be 98 inches. That still leaves an infinite number of possible rectangles.If the perimeter is 196 inches and the length has to be the longer dimension, thenit can be anything more than 49 inches, with no upper limit.For example:Width = 1 millionth of an inchLength = 1 millionth of an inch less than 98 inchesPerimeter = 196 inches.
Write a a series of equations as follows p=2l+2w (formula for perimeter) a=l*w (Formula for area) l=3w (fact given in the question) a=147 (fact given in hte question) We don't currently have enough information to solve the perimeter formula for this rectangle, so we begin with the area formula to get more information. By substituteing 147 for the variable a and 3w for the variable l, we arrive at this equation: 147=w*3w With only one variable, we can solve this equation by isolating w on one side as follows 147=3w2(Multiply w by w to combine like terms) 147/3=3w2/3 (divide both sides by 3) 49=w2 sqrt49=sqrtw2(square root of both sides) 7=w We now know that the width of the rectangle is 7. We also know that the length is three times that, which is 21. We can substitute these values into the perimeter eequation as follows: p=(2*7)+(2*21) p=14+42 p=56 The perimeter of the rectangle is 56
You can't tell. The perimeter doesn't tell you the area. There are an infinite number of rectangles that all have the same perimeter but different areas. Here are a few that all have perimeters of 28 cm: 1 x 13 . . . . . Area = 13 2 x 12 . . . . . Area = 24 3 x 11 . . . . . Area = 33 4 x 10 . . . . . Area = 40 5 x 9 . . . . . Area = 45 6 x 8 . . . . . Area = 48 7 x 7 . . . . . Area = 49
In order for an object to qualify as a cube, it must satisfy these properties: * 6 faces (like a die), 12 edges, 8 corners * all it's edges must be equal length * all it's faces have equal area If the area of the cube is 294, then the sum of it's 6 faces' area is 294 So... The area of one face is 294 ÷ 6 = 49 If all it's edges have equal length, then each face is a square. The area of a square is length × length = length = length² = 49 So... the length of one edge is the square root of 49 = 7, -7 Since you are looking for a length, -7 is not an option. The length of the edge is 7
The length of each side is seven (7) meters.
As stated the question is impossible since such a rectangle cannot exist. The area of a rectangle is measured in square units of length not in centimetres. Assuming the area is 49 square centimetres, the perimeter can be any number greater than 28 cm. Consider a rectangle of length L cm where L is any number greater than 7. Let W = 49/L cm be the width of the rectangle. Then the area of the rectangle is L*W = L*49/L = 49 cm. The perimeter can be increased by making the rectangle longer and thinner. And this can be done without any maximum limit. L can be 100 cm, 1 kilometre, 1 million kilometres, anything! Try it and see - and the perimeter is 2*(L+W)
For a square, the area is the length of a side squared and the perimeter is 4 times the length. If the area is 49, then the length of a side is 7. The perimeter is then 4 times 7, or 28.
I think this means we have a shape with a perimeter 39cm and we are asked what is the smallest area. It is a rectangle of length 19.5cm and width zero. Or perhaps it should read area 49 cm squared., what is the smallest periimeter. A circle with 49=pi x r2. Then perimeter=pi x 2r
All 4 sides of a square have equal length. If the perimeter is 28 ft, then the length of each side is 7 ft. In any rectangle, the area is (length) times (width). In the square, (length) times (width) is the same as (side squared). 72 = 49 square feet.
Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.
It can be infinitely large. Consider a rectangle of length A cm where A ≥ 7 cm. And let its width be B = 49/A cm. Then its area is always A*B cm2 = A*49/A cm2 = 49 cm2. Let A = 10 cm, B = 4.9 cm so perimeter = 29.8 cm or A = 100 cm, B = 0.49 cm, perimeter = 200.98 cm or A = 1000 cm, B = 0.049 cm, perimeter = 2000.98 cm By making the rectangle infinitesimally thin and infinitely long, its perimeter can be increased without limit.
The perimeter of the rectangle is 2•66+2•32=196196/4(sides of a square)=49 cm
Perimeter = 154 mm = 15.4 cmArea = 1,372 mm2 = 13.72 cm2
Area of a square can be calculated using the formula A = a^2, where "a" is the length of a side of the square. Its perimeter is P = 4*a. 49 = a^2 => a = 7cm P = 4*7 = 28cm The perimeter of the square is 28cm.
28 ft
The area of each square within the rectangle is 49 cm2, which is the area of a 7 cm x 7 cm square. There the length of the rectangle is 21 cm and its breadth is 7 cm.
The perimeter will be 28.