100 is the answer.
The perimeter of a rhombus with side 7 is 28 units.
The perimeter is 5 times the side length. A = 5s
Side length x 6 = perimeter
Divide the perimeter by eight.
100 is the answer.
It is: 4*5 = 20cm
The side lengths will be 14.142 cm each, giving a perimeter of 56.569 cm.
Normally, the amount of the side of the rectangle below the quarter circle on it would expected to be calculated. However, the radius of the circle equals the amount that is subtracted, but in calculating the perimeter it has to be added back in again as it forms part of the perimeter. Thus the perimeter is the perimeter of the rectangle plus a quarter of the circumference of the circle. → perimeter = 2 × (20cm + 2 cm) + ¼ × 2 × π × 11 cm ≈ 44 cm + 3.14 × 11/2 = 61.27 cm.
Perimeter = sum of all side lengths. For a square, s1 = s2 ... = s4, so Perimeter = 5+5+5+5 = 4(5) = 20cm
well, it depends on WHAT polygon that you are talking about. For example, if the figure that you were talking about was a square, then the perimeter would be sqrt20 = one side length 8sqrt5= perimeter of square and so on and so forth...
120cm (six sides x 20 = 6 x 20 = 120)
A square has all four sides the same length, so perimeter = 4 x side length.4 x 5cm = 20cm.
The area of a hexagon with a given side of 20cm is 1039.2cm2
The area of a regular hexagon with side length of 20cm is about 1039.23cm2
140 cm
A square's area is side^2. The perimeter is side*4. I'll assume you meant 25 square yards. A=25 yd=s^2 s=5 yd P=5*4 yd=20 yd