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First find its height and then use Pythagoras to find its equal sides:-

Area: 0.5*(sum of parallel sides)*height = 183.96

Height: (2*183.96)/(10.33+20.33) = 12 cm

Each side will have a right angle with bases of 5 cm

Using Pythagoras each equal side lengths are 13 cm

Perimeter therefore is: 13+13+10.33+20.33 = 56.66 cm

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9y ago
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9y ago

Area, a = 0.5*(x+y)*h where x and y are the lengths of the parallel sides.So h = 2*a/(x+y) = 12 cm.


Difference in parallel sides = 10 cm. Therefore, the "base" extends 5 cm. That is, the base, height and slanted side form a right angled triangle. Base of triangle = 5 cm, height = 12 cm. So, by Pythagoras, slant side = 13 cm.


Therefore, perimeter = 10.33 + 13 + 20.33 + 13 = 56.66 cm.

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Q: What is the perimeter of an isosceles trapezoid with parallel sides of 10.33 cm and 20.33 cm with an area of 183.96 square cm showing all work leading to the answer?
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