You can't tell. The area doesn't tell the dimensions or perimeter.
If the rectangle's area is 32 square inches, here are ten different perimeters that it could have.
ALL of these have 32 square inches of area, and there are many, many more:
0.8 x 40 . . . . . . Perimeter = 81.6 inches
1 x 32 . . . . . . . Perimeter = 66 inches
1.25 x 25.6 . . . Perimeter = 53.7 inches
1.6 x 20 . . . . . . Perimeter = 43.2 inches
2 x 16 . . . . . . . Perimeter = 36 inches
2.5 x 12.8 . . . . Perimeter = 30.6 inches
3.2 x 10 . . . . . Perimeter = 26.4 inches
4 x 8 . . . . . . . Perimeter = 24 inches
5 x 6.4 . . . . . Perimeter = 22.8 inches
51/3 x 6 . . . . Perimeter = 222/3 inches
32 square inches.
Let x and y be the dimensions of the rectangle. Therefore, x+y=107 and x*y=2310. The question is the find two real numbers such that they satisfy the above statement. There are x=77 and y=32 that satisfy the statement above
The area of a rectangle is found by using the formula A=LxW (Area equals length times width)The area of a rectangle is calculated by multiplying the length by the width - the result is square measure. A rectangle 6 inches by 8 inches would be 48 square inches in area. (6x8=48)ExampleA=LxWA=4x5A=20
For example, a 1x15 rectangle and a 2x14 rectangle. They both have perimeter of 32, but they have areas of 15 and 28, respectively.
32.
Perimeter = 32 inches. Area = 55 square inches.
32 inches
A square with a perimeter of 32 inches has an area of 64 square inches.
The square's area is 36 in2 while the rectangle's is 32. So the square has the greater area.
They will be both the same because the perimeter of the square is 32 units and the perimeter of the rectangle is also 32 units
47
The perimeter of the rectangle is 2•66+2•32=196196/4(sides of a square)=49 cm
To find the least perimeter of a rectangle with a fixed area of 32 square feet, we can use the relationship between area and perimeter. For a rectangle, the area ( A = l \times w ) (length times width) and the perimeter ( P = 2(l + w) ). To minimize the perimeter while keeping the area constant, the rectangle should be a square. The side length of a square with an area of 32 ft² is ( \sqrt{32} ), which is approximately 5.66 ft. Thus, the least perimeter is ( 4 \times \sqrt{32} ), which is approximately 22.63 ft.
The least perimeter is attained when the rectangle is, in fact a square. A square with an area of 32 square feet will have sides of sqrt(32) = 4*sqrt(2) ft. So the perimeter of the square will by 4*4*sqrt(2) = 16*sqrt(2) = 22.63 feet, approx.
If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.
32 square inches.
The area of a rectangle with a perimeter of 32 units and a width of 6 units the area is 80 square units.Improved Answer:-Area = 6*10 = 60 square unitsPerimeter = 6+6+10+10 = 32 units