You can't tell. The area doesn't tell the dimensions or perimeter.
If the rectangle's area is 32 square inches, here are ten different perimeters that it could have.
ALL of these have 32 square inches of area, and there are many, many more:
0.8 x 40 . . . . . . Perimeter = 81.6 inches
1 x 32 . . . . . . . Perimeter = 66 inches
1.25 x 25.6 . . . Perimeter = 53.7 inches
1.6 x 20 . . . . . . Perimeter = 43.2 inches
2 x 16 . . . . . . . Perimeter = 36 inches
2.5 x 12.8 . . . . Perimeter = 30.6 inches
3.2 x 10 . . . . . Perimeter = 26.4 inches
4 x 8 . . . . . . . Perimeter = 24 inches
5 x 6.4 . . . . . Perimeter = 22.8 inches
51/3 x 6 . . . . Perimeter = 222/3 inches
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32 square inches.
Let x and y be the dimensions of the rectangle. Therefore, x+y=107 and x*y=2310. The question is the find two real numbers such that they satisfy the above statement. There are x=77 and y=32 that satisfy the statement above
The area of a rectangle is found by using the formula A=LxW (Area equals length times width)The area of a rectangle is calculated by multiplying the length by the width - the result is square measure. A rectangle 6 inches by 8 inches would be 48 square inches in area. (6x8=48)ExampleA=LxWA=4x5A=20
32.
For example, a 1x15 rectangle and a 2x14 rectangle. They both have perimeter of 32, but they have areas of 15 and 28, respectively.