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First you need to figure out the probability of it not landing on a 2 when you roll one die. Since there are six sides and two sides with 2 on it, the probability that one die will not land on 2 is 4/6.

Now you multiply 4/6 by 4/6 to find the correct odds as to both die not landing on 2.

4/6 * 4/6 = 16/36 = 4/9

The percentage is (4/9)*100% = (approx.) 44.4%

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Q: What is the probability of two dice that have a 1 side with a one 2 sides with two on it and 3 sides with 3 on it. and not getting a 2 when you role both?
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