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Q: What is the probability that the sum of the dice is odd and both dice show the number 3?

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Probability zero. If both dice have the same number, then the result will be even. If both dies are odd (as in the case of 5) then the sum is even. If both dies are even, the sum is also even. The only way to get an odd sum is to have one die have an odd number and the other die have an even number. That will happen 50% of the time.The probability of both dice showing 5 is 1/36. But the two events will never happen at the same time.

5/36

9/11

It is 7/8.

there is a probability of 1/6.Answer:For two dice to show 5 and 2:There are two ways to roll a "good" number (2 or 5) for the first dice. This gives odds of 2/6.For the second dice there is one way to role a good number ( 1 in 6)The odds to roll both a 2 and a 5 are (2/6)x(1/6) or 2/36 or 1/18.

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The probability is 0 since if both dice show the number 6, their sum is 12 which is not a prime.

Probability zero. If both dice have the same number, then the result will be even. If both dies are odd (as in the case of 5) then the sum is even. If both dies are even, the sum is also even. The only way to get an odd sum is to have one die have an odd number and the other die have an even number. That will happen 50% of the time.The probability of both dice showing 5 is 1/36. But the two events will never happen at the same time.

There are 6 × 6 = 36 possible outcomes There are 3 odd numbers, so there are 3 × 3 = 9 results that are a success → probability of both dice showing an odd number = 9/36 = 1/4

Assuming you mean the sum of the two dice is a prime number, then: The possible outcomes are 2, 3, 5, 7, 11 which occur 1, 2, 4, 7, 2 times respectively. There are 36 possible outcomes → pr(prime_sum) = (1+2+4+7+2)/36 = 16/36 = 4/9 If you mean that both dice must show a prime number, then: The possible primes are 2, 3, 5 → probability of 1 die showing a prime number is 3/6 = ½ → probability both show a prime number is ½ × ½ = ¼ If you mean either or both dice could show a prime number, then: The possible primes are 2, 3, 5 → probability of 1 die showing a primes is 3/6 = ½ → probability of a die not showing a prime is 1 - ½ = ½ → probability of neither die showing a prime is ½ × ½ = ¼ → probability of either or both dice show a prime is 1 - ¼ = ¾

The first dice can show any number. However the second dice has a 1 in 6 chance of being the same as the first. Hence the probability of getting two numbers the same is 1/6.

5/36

It is 0.8181... recurring.

9/11

We calculate the numerator of the desired probability: There are 6 ways any number can show up on the first die AND There is only 1 way that same number can show up on the second die So since "AND" means "MULTIPLY", there are 6x1 or 6 ways that both dice can come up the same. So the numerator of the probability is 6. We calculate the denominator of the desired probability: There are 6 ways any number can show up on the first die AND There are 6 ways any number can show up on the second die So since "AND" means "MULTIPLY", there are 6x6 or 36 ways the two dice can all come up any number. So the denominator of the probability is 36.

It is 7/8.

The probability of rolling doubles on a pair of dice is 1 in 6, or about 0.1667.

4/11

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