If the radius of the sphere is R units then the radius of the cross section is sqrt(R2 - 32)
Therefore the cross sectional area is pi*(R2 - 32) square units.
A Basketball is a sphere so a cross-section would be a circle.
A basketball is a sphere so a cross-section would be a circle.
always a circle.
A circle
a circle !
That depends on how many units there are in the diameter of the sphere. * * * * * If the radius of the sphere is R units then the radius of the cross section is sqrt(R2 - 122) Therefore the cross sectional area is pi*(R2 - 122) square units.
The cross section at this point forms a circle and its area is pi/32 which equals 9*pi square units. * * * * * Not quite. If the radius of the sphere is R units then the radius of the cross section is sqrt(R2 - 32) Therefore the cross sectional area is pi*(R2 - 32) square units.
Every cross-section of a sphere is a circle.
A basketball is a sphere so a cross-section would be a circle.
A Basketball is a sphere so a cross-section would be a circle.
always a circle.
A circle.
A circle.
yes
A two-dimensional cross-section of a sphere is represented by a circle. When a plane intersects a sphere, the intersection forms a circular shape, with the size of the circle varying depending on how the plane cuts through the sphere. If the plane passes through the center of the sphere, the resulting circle will have the largest diameter, while other intersections will produce smaller circles.
When a sphere is cut with a vertical angled plane, the cross-section will be an ellipse. If the sphere is then cut by a horizontal plane, the cross-section will be a circle. Thus, the combination of these two cuts results in an elliptical cross-section from the angled cut and circular cross-sections from the horizontal cuts at various heights.
Every section of a solid sphere is a filled-in circle, i.e. a disk with zero thickness.