Surface area: 4*pi*radius2 = 28
Making the radius the subject of the above gives it a value of 1.49270533 or about 1.5 inches
Surface area of ball: 4*pi*1^2 = 4*pi square feet
Radius = square root of (153.94/4pi) = 3.5 to one decimal place
First find the radius by dividing 19 by 2*pi which is 3.023943919 cm Surface area of a sphere (the ball) = 4*pi*radius2 Surface area = 4*pi*3.0239439192 => 114.9098689 Surface area of the ball: 115 square centimeters correct to three significant figures.
They are spheres. They cannot therefore have different geometrical properties. To alter surface to volume ratios you would need to alter the shape. The study of mathematical shapes is called topology.
To a first approximation, a tennis ball is a sphere. The volume of a sphere is V = 4/3 π r3, where r is the radius of the sphere. So measure the diameter of the tennis ball, divide by 2 to get the radius, and then apply the formula above. You could also measure the volume of a tennis ball by measuring the volume of water that it displaces.
To increase the surface area-to-volume ratio of a basketball, you can deflate it slightly, which will cause it to have more wrinkles and bumps on its surface. For a tennis ball, you can cut it into smaller pieces, such as quarters, which will increase the surface area relative to its volume.
Surface area of a ball or a sphere = 4*pi*radius squared
Surface area of a sphere = 4*pi*radius2
Surface Area is the term used to describe the area of an object that is exposed. In other words, if you took a tennis ball, the outside of the ball is it's surface area. If you cut the tennis ball in half, the original outside part is still part of the surface area but now include the inside as well.
66.98 sqcm
4 pie ft. 2
A soccer ball has a larger radius than a baseball, so it has more surface area.
40 millimeters
Surface area of ball: 4*pi*1^2 = 4*pi square feet
Radius = square root of (153.94/4pi) = 3.5 to one decimal place
Surface area of a sphere = 4πr²A= 4(3.14159) X 1A= 12.56 ft²
the more surface area, the more friction, the more the drag