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How do you write a quadratic equation using only solutions 10 and -2?
12
How do is 2x plus 8 equals x plus 10?
To solve the equation 2X+8=X+10 the first step is to get all instances of the variable 'X' on the same side of the 'equals' sign. To do this, we must first subtract 'X' from both sides of the equation: 2X+8-X=X+10-X which then becomes X+8=10. The next step is to leave the variable 'X' alone on it's side of the 'equals' by subtracting the numeral 8 from both sides of the equation: X+8-8=10-8 which then becomes X=2. To confirm that the solution is correct, we then substitute the solution we arrived at into the original equation in place of the variable 'X': 2*2+8=2+10 2*2=4 so: 4+8=2+10 4+8=12 and 2+10=12 so the final solution is: 12=12 Therefore the answer to the question "Is 2X+8 equal to X+10" is Yes, and the value of the variable 'X' is 2
When you square each side of an equation is the resulting equation equivalent to the original?
No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2
What equation correctly represents a circle centered at the origin with a radius of 10?
x^2 + y^2 = 100
The equation for the circle is x2 plus y2 equals 100. What is the length of the circles radius?
x^2 + y^2 = 100 (x - 0 )^2 + ( y - 0)^2 = 10^2 This is now in the Pythagorean form. x^2 + y^2 = r^2 The centre in Cartesian coordinates is the displacement of (x,y). Since there is no displacement , the the centre is at (0,0) r^2 is the radius squared at 10^2 , then the radius has a length of '10'.
