Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
Write the quadratic equation in the form ax2 + bx + c = 0 then the roots (solutions) of the equation are: [-b ± √(b2 - 4*a*c)]/(2*a)
write an algorithm to find the roots of a quadratic equation
Just write the equation as: (x - 11)(x - 3) = 0 and convert it to any form you like.
The most straightforward way to do this is to use the quadratic equation.
Write the quadratic equation in the standard form: ax2 + bx + c = 0 Then calculate the discriminant = b2 - 4ac If the discriminant is greater than zero, there are two distinct real solutions. If the discriminant is zero, there is one real solution. If the discriminany is less than zero, there are no real solutions (there will be two distinct imaginary solutions).
readuse the answer
Simply write that "no solutions are available for <equation>".
(x + 5) (x + 1) = 0x2 + 6x + 5 = 0
lol no betch