The sine and cosine of acute angles are equal only for 45° sin45° = cos 45° = 1/sqrt(2) = 0.7071
at a 45 degree angle, or pi/4
sin-1(0.707) = 44.99134834 or about 45 degrees
a TRIANGLE HAS 180 DEGRESS! a new born knows that! LOL
The sine of 0 is 0.
sine 45 = 0.850903525
By shifting the sine wave by 45 degrees.
You mean, "N in 45 degrees"? Ans. sine(45) = 0.7071 N
45 N 25 E is Davidești, Romania.
The sine and cosine of acute angles are equal only for 45° sin45° = cos 45° = 1/sqrt(2) = 0.7071
A point in the Atlantic ocean
Yes. Acute is anything less than 90.
To find which angle has a sine of 0.13, you calculate arcsin or sin^-1(0.13) =7.47 degrees 7.47 degrees has a sine of 0.13. There is also another angle , below 360 , has a sine of 0.13. Subtract 7.47 from 180. 180-7.47 = 172.53 degrees also has a sine of 0.13.
The square root of two over two.
at a 45 degree angle, or pi/4
1 it can not used when the angle more than 45 degrees.....
We know that sin @ = h/l is the basic principle of working of sine bar.Differentiating above equation,.. . cos @ . d@ = l.dh - h.dl_________ l*ld@ =tan@(dh/l - dl/l)This indicate that error is a function of tan @ and below 45 degree error is smaller which suddenly increases above 45 degree. because of this reason sine bar is preferred for measuring angle below 45