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How do write an equation of a line when given the slope a point of the line?
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
What is the point slope equation for the line that passes through the point (55)?
There are infinitely many lines that pass through the point (5, 5). The point slope equation for a straight line with a given slope m through a point (x0, y0) is given by: y - y0 = m(x - x0) Which means that the straight line through the point (5, 5) will have an equation of the form: y - 5 = m(x - 5) where m is the slope of the line - you'll need to replace that with the slope you require.
What is the slope of the line given by the equation y 11x 5?
y = 11x + 5 The slope/gradient of this equation is 11. The slope/gradient can easily been seen in a linear equation: it is simply the co-efficient of x
What is the slope of the line perpendicular to the line passing through the points 5-1 and 2-5?
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
What is the slope and y-intercept of the line given by the equation y equals -5x?
The slope is -5. The x- and y-intercepts are both zero. In other words, it passes through the origin.
