if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
There are infinitely many lines that pass through the point (5, 5). The point slope equation for a straight line with a given slope m through a point (x0, y0) is given by: y - y0 = m(x - x0) Which means that the straight line through the point (5, 5) will have an equation of the form: y - 5 = m(x - 5) where m is the slope of the line - you'll need to replace that with the slope you require.
y = 11x + 5 The slope/gradient of this equation is 11. The slope/gradient can easily been seen in a linear equation: it is simply the co-efficient of x
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
The slope is -5. The x- and y-intercepts are both zero. In other words, it passes through the origin.
If you mean: y = 3x+5 then it is a straight line equation that can be plotted on a graph whereas 3 is the slope and 5 is the y intercept
If you mean: y = 3x-5 then the slope is 3 and the y intercept is -5
If you mean: y = 3x-5 then the slope is 3 and the y intercept is -5
-5/3
4
The slope is 5.
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
The slope is 1 and the y intercept is 5
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
5
It is: 5