There are infinitely many lines that pass through the point (5, 5).
The point slope equation for a straight line with a given slope m through a point (x0, y0) is given by:
y - y0 = m(x - x0)
Which means that the straight line through the point (5, 5) will have an equation of the form:
y - 5 = m(x - 5)
where m is the slope of the line - you'll need to replace that with the slope you require.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
y = 7
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
The equation works out as: y = 5x+7
The equation is x = -7.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
33
write an equation that has a slope 7 and passes through the point (2,17)
Point: (1, 4) Slope: -3 Equation: y = -3x+7
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
If you mean a point of: (-4, 7) and a slope of 4 Then the equation works out as: y = 4x+23
The equation is: y = 4x-22
Slope=8 point=(-7,3)
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
y = 7
y = 5