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Barry Sneed

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3y ago

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What is the sum of the interior angles of a 22 sided polygon?

(22-2)*180=3600


What is the sum of the measures in degrees of the interior angles of a 22-sided polygon?

3600


What is the sum for a 22 sided figure?

The sum of the interior angles of a 22-sided polygon (icosikaitriangle) can be calculated using the formula ((n - 2) \times 180) degrees, where (n) is the number of sides. For a 22-sided figure, the sum of the interior angles is ((22 - 2) \times 180 = 20 \times 180 = 3600) degrees. Therefore, the sum of the interior angles of a 22-sided polygon is 3600 degrees.


How many degrees are in a 22 sided polygon?

To find the sum of the interior angles of a polygon, you can use the formula ( (n - 2) \times 180 ), where ( n ) is the number of sides. For a 22-sided polygon, the calculation is ( (22 - 2) \times 180 = 20 \times 180 = 3600 ) degrees. Therefore, the sum of the interior angles in a 22-sided polygon is 3600 degrees.


What is the sum of the messures in degrees of the interior angles of a 22 sided polygon?

3600 degrees


What is the angle sum for a 22 sided polygon?

Exterior angles: 360 degrees Interior angles: 3,600 degrees


What is the measurement of the interior angles of a 3 sided polygon or other polygons up to a 22 sided polygon?

The formula is: (n-2)*180 = sum of interior angles whereas 'n' is the number of sides of the polygon.


What would each angle be if you have a 22 sided polygon with the sum of the angles being 3600?

163.64 degrees


What is the sum of the interior angles in a 22 sided polygon?

There is a formula you can use to determine the sum of the interior angles of any polygon with n number of sides:(n-2) * 180oso in your case it would be (22-2)*180o = 3600o


What are the exterior angles on a 20 sided polygon?

The sum of the exterior angles of any polygon and the extension of its adjacent side is 360 degrees.If the 20 sided polygon is regular, then each angle is equal so that each one is 360/20 = 18 degrees.


Interior angles of polygon with 22 sides?

The sum of the interior angles of a polygon can be calculated using the formula ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides. For a polygon with 22 sides, the sum of the interior angles is ( (22 - 2) \times 180^\circ = 20 \times 180^\circ = 3600^\circ ). Each interior angle of a regular 22-sided polygon would therefore be ( \frac{3600^\circ}{22} \approx 163.64^\circ ).


Why do you subtract 2 when calculating the interior degrees of a 24 sided polygon?

Basically when you have a 24 sided polygon you can split it up into 22 separate, non-overlapping triangles by drawing diagonals. Each triangle has 180 degrees, so the product, 22 times 180, gives you the sum of the interior angles of the 24 sided polygon.