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Square: A = s^2 = 500

s^2 = 500

s = √500

s ≈ 22.36

P = 4s = 4 x 22.36 = 89.44

Equilateral triangle: side s (congruent sides)

A = (1/2)(s)[(1/2)s] (since the altitude from one vertex is also the median of the side opposite to it)

A = (1/4)s^2 = 500

(1/4)s^2 = 500 multiply by 4 to both sides

s^2 = 2,000

s = √2,000

s ≈ 44.72

P = 3 x 44.72 = 134.16

P(square) + P(triangle) = 89.44 + 134.16 = 223.6 ≈ 224

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Q: What is the sum of the perimeters of a square and an equilateral triangle that each have an area of 500 meters square?
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