An equilateral triangle would fit the given description
A square would fit the given description
A square would fit the given description
-- An 'acute triangle' is a triangle in which each of the three interior angles is an acute angle. -- Each of the three interior angles in every equilateral triangle is a 60-degree angle. -- Any angle of less than 90 degrees is an acute angle. -- It sure looks like every equilateral triangle does fit the definition of 'acute triangle'.
A triangle CAN fit that description, if it is "equilateral" (equi means equal, later- means sides, so "equilateral" means all sides are equal). If all sides are equal then all angles will be, too.
A square and rectangle all fit this description.
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An equilateral triangle would fit the given description
The question appears to be incomplete, but an equilateral triangle, seems to fit the answer.
No, two equilateral triangles do not make a square. A square has four equal sides and four right angles, while an equilateral triangle has three equal sides but three angles that add up to 180 degrees. When two equilateral triangles are put together, they do not form a shape with four equal sides and four right angles, which is the defining characteristic of a square.
An equilateral triangle would fit the given description
A square would fit the given description
A square would fit the given description
-- An 'acute triangle' is a triangle in which each of the three interior angles is an acute angle. -- Each of the three interior angles in every equilateral triangle is a 60-degree angle. -- Any angle of less than 90 degrees is an acute angle. -- It sure looks like every equilateral triangle does fit the definition of 'acute triangle'.
A triangle CAN fit that description, if it is "equilateral" (equi means equal, later- means sides, so "equilateral" means all sides are equal). If all sides are equal then all angles will be, too.
The circle - the rest are polygons.
Cube, because it is 3 - dimensional while a square, an oval, a circle, and a triangle are all 2 dimensional.