as you are trying to work out the area. W x L = area. So. 5m x 6m = 30m2
use the net to find the lateral area of the prism 3m 6m 3m 6m 15m
1m = 100cm so 60cm x 40 cm x 40 cm = .6m x .4m x .4m = .096m^2
The area of a square is calculated by squaring the length of one of its sides. In this case, the side of the square field is 6 meters, so the area would be 6m x 6m = 36 square meters.
74
1m times 5m times 6m
To calculate the volume of a box, you multiply its length, width, and height. In this case, the box measures 1m x 5m x 6m. Therefore, the volume would be 1m x 5m x 6m = 30 cubic meters. So, the volume of the box is 30 cubic meters.
It is: 11*5*6 = 330 cubic meters
-8 + (5m - 6m) = -8 + (-m) = -8 - m
-1
Volume = 1/3*pi*52*6 = 50*pi cubic m
1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.
You would need to dilute the 6M acetic acid solution by adding the appropriate volume of water. To prepare 500 mL of 1M solution, you would need to take (1/6)th of the volume of the 6M solution, which is (1/6) x 500 mL = 83.33 mL of the 6M solution. Dilute this with water to reach a final volume of 500 mL.
11
30 m^2
To find the volume of water needed to refill the pool, you multiply the dimensions of the pool together: 6m x 5m x 3m = 90 cubic meters. You would need to purchase 90 cubic meters of water to refill the pool.
To make a Tris buffer at pH 7.5, you will need to mix Tris base with HCl. To calculate the volume of 5M HCl needed, you will first need to determine the molarity of the Tris buffer solution and then use the Henderson-Hasselbalch equation. The exact volume of 5M HCl required will depend on the amount of Tris base used and the final volume of the buffer solution.