lenght=15, width= 10
Length of rectangle garden is 5 m greater than the width. the area is 84 m2. find the dimensions of the garden.
Let the length be 2x and the width be x: length*width = area 2x*x = 50 2x2 = 50 x2 = 25 x = 5 feet
Surface area = 2*(L*W + W*H + H*L) = 324 m2
Rectangular perimeter = 2(Length + Width) Width = a Length = a+5 Then, 84 = 2(a+a+5) 42 = 2a+5 (42-5)/2 = a = 18.5m = Width Length = a+5 = 23.5m
the width of the rectangle is 12.....because area= lenght x width so if the lenght is 5 inches and the area is 60....u divide 60 divided by 5 = 12
lenght=15, width= 10
375 375
Length of rectangle garden is 5 m greater than the width. the area is 84 m2. find the dimensions of the garden.
5 meters Check: 5+5+2+2 = 14 meters
10*7*5 =350 cubic centimetres.
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
Let the length be 2x and the width be x: length*width = area 2x*x = 50 2x2 = 50 x2 = 25 x = 5 feet
5 cm2 = 5 * 1 cm* 1 cm = 5 * 0.01 m *0.01 m = 5 * 0.0001 m2 = 0.0005 m2
In American Football, the distance between the uprights is 18.5 feet.
A = lw 60 = l * 50 l = 60 / 50 l = 6/5 m
if the angle is 90 degrees, 5 x 9,8 = T