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Q: What is the volume of a cone that has a base with a radius of 4 inches and a height of 12 inches?

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A cylinder with a base radius of 4 units and a height of 9 units has a volume of 452.39 units3

5.07 inches

volume=pi*radius squared*height/3, where radius is the radius of the cylinder (and will be the radius of the base of the cone),and height is the lenth of the cylinder.

A cone with a base radius of 2 units and a height of 19 units has a volume of 79.59 cubic units.

A cone with a base radius of 6 units and a height of 11 units has a volume of 414.69 cubic units.

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A cone with a base radius of 9.9 inches and a height of 14 inches has a volume of 1,436.9 cubic inches.

A cone with a base radius of 6 inches and a height of 8 inches has a volume of 301.59 cubic inches.

A cone with a base radius of 9.9 inches and a height of 14 inches has a volume of 1,436.9 inches3

A cone with a perpendicular height of nine inches and a base radius of three inches has a volume of: 84.823 cubic inches.

A cone with a base radius of 8 inches and a height of 8 inches has a volume of 536.17 cubic inches.

226.19 cubic inches.

The volume is base x height, or pi x radius2 x height.

if its a cone: volume= (1/3) base* height or volume= (1/3) pi *radius*radius[r squared]* height

If the volume of a cylinder is 300 and the height is 3, the radius of the base is: 5.65

Volume = Base*Height So Height = Volume/Base = 185.13/15.3 = 12.1 inches.

Volume = Base x Height /3 Where base is the area of the base circle (pi*radius*radius) and Height is the perpendicular distance from the base to the apex of the cone

A cylinder with a base radius of 4 units and a height of 9 units has a volume of 452.39 units3

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