The volume of a cone is exactly equal to one third the volume of a cylinder of equal height and radius. The volume of a cylinder is equal to πr2h, so the volume of a cone is πr2h/3
If the area of the base and the height of the cylinder and the cone are the same, then the volume of the cone will always be one third of the volume of the cylinder.
Pretty sure it's a 1/3 of the volume of the cylinder so it would be 100 cm^3
multiply the volume of the cylinder by 1/3. whatever you get is the volume of the cone
If you look at the formulas for volume of a cone and volume of a cylinder you can see that a cone will fit in exactly three times if the height and radius of the cone and cylinder are equivalent. A cone has the equation: (1/3)*pi*(r^2)*h=Volume. And a cylinder has the equation: pi*(r^2)*h=Volume. With h equaling height and r equaling radius, you can see that 3*(Volume of a cone)=Volume of a cylinder. Therefore, the cone would fit in three times if height and radius are equivalent for the two figures.
The cone has 1/3 of the volume of the cylinder.
The volume of a cone is 1/3 of the volume of a cylinder with the same radius and height
The volume of a cone is one third the volume of a cylinder of the same height. The volume of a cylinder is πr2h, so the volume of a cone is 1/3πr2h.
Separate them into parts. First calculate the volume of the cylinder, then the cone and then add the results
A cylinder has a height of 16 cm and a radius of 5 cm. A cone has a height of 12 cm and a radius of 4 cm. If the cone is placed inside the cylinder as shown, what is the volume of the air space surrounding the cone inside the cylinder? (Use 3.14 as an approximation of π.)
It depends on their radii and heights.