Volume of a cone = 1/3*pi*radius2*height
Radius = 9pi/2pi = 4.5 cm
Height using Pythagoras = 6 cm
Volume = 1/3*pi*4.52*6 = 127.235 cm3 rounded to 3 decimal places
Total surface area = (piradius2)+(piradius*slant length)
The volume of a cube whose side length is 4 cm is: 64 cm3
The length of a side of a cube whose volume is 25cm3 is 5 centimeters.
The volume of a cylinder whose length is 8 with a radius of 3 is: 226.2 cubic units.
8
The volume of this cone is 37,699 cm3
The length of the diameter of a circle whose circumference is 62.8 is about 20 units (19.99). (d = c divided by Pi)
V = 37,700 cm3
Total surface area = (piradius2)+(piradius*slant length)
The volume of a cube whose side length is 4 cm is: 64 cm3
circumference = 2*pi*5 feet
The length of a side of a cube whose volume is 25cm3 is 5 centimeters.
The volume of a cylinder whose length is 8 with a radius of 3 is: 226.2 cubic units.
The length (edge length) of a cube with a volume of 44.4 liters is: 1.162 feet.
Volume = s3
First find the slant length using the following formula:- Formula: (pi*radius2)+(pi*radius*slant length) = entiresurface area So: (3.14*5.252)+(3.14*5.25*slant length) = 230.79 Dividing all terms by 3.14*5.25: 5.25+slant length = 14 Subtract 5.25 from both sides: slant length = 8.75 Use Pythagoras to find height: 8.752-5.252 = 49 and sq rt is 7 Therefore: slant length = 8.75 cm and perpendicular height = 7 cm
A right circular cone whose slant height is 9 inches and whose base has a diameter of 2 inches will have a volume of 36.757 cubic inches.