X intercept is where it intersects the X-axis, which is where y = 0. So set y=0 in the equation, and solve for x. 5x - 2(0) = 10 --> 5x = 10 --> x = 2. So the point (2,0) is where the x-intercept is.
6x = 10-y y = -6x+10 The slope is -6 and the y intercept is 10
4x-2y = 10 -2y = -4x+10 y = 2x-5 which is now in slope-intercept form
If you mean: y=-5x+10 and the point (3, 10) then the parallel equation is y=-5x+25
6x - 36y = 36 (divide each term of both sides by 6)x - 6y = 6 (subtract x from both sides)- 6y = -x + 6 (divide each term of both sides by -6)y = (1/6)x - 1 this is the slope intercept form of the equation of a line, where -1 is the y-intercept.To find the x-intercept, substitute 0 for y into the last equation. So we havey = (1/6)x - 10 = (1/6)x - 1 (add 1 to both sides)1 = (1/6)x (multiply both sides by 6)6 = xThus, the y-intercept is -1, and the x-intercept is 6.
15
15
-2
10
(5, 0)
10
5x - 2y = 10 2y = 5x - 10 y = 2.5x - 5......which is the equation in slope intercept form.
15
15
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
8
It is a straight line equation which can be rearranged to y = 3x+10 in slope intercept form