6x - 36y = 36 (divide each term of both sides by 6)
x - 6y = 6 (subtract x from both sides)
- 6y = -x + 6 (divide each term of both sides by -6)
y = (1/6)x - 1 this is the slope intercept form of the equation of a line, where -1 is the y-intercept.
To find the x-intercept, substitute 0 for y into the last equation. So we have
y = (1/6)x - 1
0 = (1/6)x - 1 (add 1 to both sides)
1 = (1/6)x (multiply both sides by 6)
6 = x
Thus, the y-intercept is -1, and the x-intercept is 6.
-5x + 6y = 30At the x-intercept, y=0:-5x = 30 ==> x = -6At the y-intercept, x=0:6y = 30 ==> y = 5
You can solve your algebra question like this: Example; n+6=16. You are going to need to find out what the N equals to. __+6=16 So you need to find out what the N equals to. You can also solve it like this: 16-6=10. So, 10 is the answer to the equation.
Write an algorithm to find the root of quadratic equation
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
24
The equation 9=3y has the x-intercept (0,0) and the y-intercept (0,3).
The vertex must be half way between the two x intercepts
It is 6000.
If "a" is negative then the graph is a cap. Find the x intercepts. Average the two x intercepts and substitute that into the equation it will give you the y.
Slope: -1 intercepts: (0,1000),(1000,0)
When y is 0 then x intercept is at (10, 0) When x is 0 then y intercept is at (0, -12)
Graph the equation then find the x intercepts.
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
I believe that you need an equation to solve for the x and y intercepts.
the measure of a minor arc equals the measure of the central angle that intercepts it.
x2 + y - 49 = 0At the x-intercepts, y=0:x2 - 49 = 0(x+7)(x-7) = 0x = -7 and x = +7At the y-intercept, x=0:y - 49 = 0y = 49