6x - 36y = 36 (divide each term of both sides by 6)
x - 6y = 6 (subtract x from both sides)
- 6y = -x + 6 (divide each term of both sides by -6)
y = (1/6)x - 1 this is the slope intercept form of the equation of a line, where -1 is the y-intercept.
To find the x-intercept, substitute 0 for y into the last equation. So we have
y = (1/6)x - 1
0 = (1/6)x - 1 (add 1 to both sides)
1 = (1/6)x (multiply both sides by 6)
6 = x
Thus, the y-intercept is -1, and the x-intercept is 6.
-5x + 6y = 30At the x-intercept, y=0:-5x = 30 ==> x = -6At the y-intercept, x=0:6y = 30 ==> y = 5
You can solve your algebra question like this: Example; n+6=16. You are going to need to find out what the N equals to. __+6=16 So you need to find out what the N equals to. You can also solve it like this: 16-6=10. So, 10 is the answer to the equation.
Write an algorithm to find the root of quadratic equation
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
24
The equation 9=3y has the x-intercept (0,0) and the y-intercept (0,3).
The vertex must be half way between the two x intercepts
It is 6000.
If "a" is negative then the graph is a cap. Find the x intercepts. Average the two x intercepts and substitute that into the equation it will give you the y.
Slope: -1 intercepts: (0,1000),(1000,0)
When y is 0 then x intercept is at (10, 0) When x is 0 then y intercept is at (0, -12)
Graph the equation then find the x intercepts.
To determine the intercepts of a line, you need to find where the line crosses the x-axis and y-axis. The x-intercept occurs when y = 0, and the y-intercept occurs when x = 0. If you have the equation of the line, you can substitute these values to find the respective intercepts. Please provide the equation of the line for specific intercept values.
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
I believe that you need an equation to solve for the x and y intercepts.
the measure of a minor arc equals the measure of the central angle that intercepts it.