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6x - 36y = 36 (divide each term of both sides by 6)
x - 6y = 6 (subtract x from both sides)
- 6y = -x + 6 (divide each term of both sides by -6)
y = (1/6)x - 1 this is the slope intercept form of the equation of a line, where -1 is the y-intercept.
To find the x-intercept, substitute 0 for y into the last equation. So we have
y = (1/6)x - 1
0 = (1/6)x - 1 (add 1 to both sides)
1 = (1/6)x (multiply both sides by 6)
6 = x
Thus, the y-intercept is -1, and the x-intercept is 6.
What else can I help you with?
Find the coordinates of the x and y intercepts of -5x plus 6y equals 30?
-5x + 6y = 30At the x-intercept, y=0:-5x = 30 ==> x = -6At the y-intercept, x=0:6y = 30 ==> y = 5
How do you solve an algebra problem?
You can solve your algebra question like this: Example; n+6=16. You are going to need to find out what the N equals to. __+6=16 So you need to find out what the N equals to. You can also solve it like this: 16-6=10. So, 10 is the answer to the equation.
Find an equation of the line having the given slope and containing the given point m equals 2 over 3 and 2 and -1?
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
Write an algorithm to find the root of quadratic equation?
Write an algorithm to find the root of quadratic equation
What represents the vertex and two x-intercepts of y equals x2-2x-35?
(1,-36); -5 and 7y = x2-2x-35; f(x) = ax2+bx+cvertex, method 1:There is a formula for the vertex, if you can remember it. (h,k) = [-b/2a, f(-b/2a)].-b/2a = 2/2x1 = 2/2 = 1. f(1) = 12-2x1-35 =1-2-35 = -36. The vertex is (1,-36).vertex, method 2:Otherwise you complete the square to convert to the vertex form, y = a(x-h)2 + k. Complete the square for x2-2x: the constant term will be (-2/2)2 = (-1)2 = 1.y = (x2-2x+1)-1-35 = (x-1)2 -36 ==> The vertex is (h,k) = (1,-36).x-intercepts, method 1:To find the x-intercepts, let y=0: 0 = x2-2x-35 (x-7)(x+5) = 0 x-7=0 or x+5=0 x=7 or x=-5. The intercepts are -5 and 7.x-intercepts, method 2:There is also a nice trick to find the intercepts: 36 = 62. the intercepts are 1+/- 6 = 7 and -5.
Find the X and Y intercepts of 9 equals 3 y?
The equation 9=3y has the x-intercept (0,0) and the y-intercept (0,3).
How would you use intercepts to find the vertex in a quadratic equation with two x intercepts?
The vertex must be half way between the two x intercepts
How do you find the intercepts of F of X equals 6000 - 75x?
It is 6000.
How do you find the maximum height of a parabolic path?
If "a" is negative then the graph is a cap. Find the x intercepts. Average the two x intercepts and substitute that into the equation it will give you the y.
Find the slope and intercepts of each line y equals -x plus 1000?
Slope: -1 intercepts: (0,1000),(1000,0)
How do you find the x and y-intercepts for the graph of the equation 6x-5y equals 60?
When y is 0 then x intercept is at (10, 0) When x is 0 then y intercept is at (0, -12)
What is the formula to find the intercepts for a quadratic equation?
To find the intercepts of a quadratic equation in the standard form ( y = ax^2 + bx + c ), the y-intercept can be found by evaluating the equation at ( x = 0 ), which gives the point ( (0, c) ). For the x-intercepts, set ( y = 0 ) and solve the equation ( ax^2 + bx + c = 0 ) using the quadratic formula ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). The resulting values of ( x ) will give the x-intercepts.
What are the intercepts of this line?
To determine the intercepts of a line, you need to find where the line crosses the x-axis and y-axis. The x-intercept occurs when y = 0, and the y-intercept occurs when x = 0. If you have the equation of the line, you can substitute these values to find the respective intercepts. Please provide the equation of the line for specific intercept values.
How do you use a graphing calculator to solve quadratic equations?
Graph the equation then find the x intercepts.
How to find the x-intercepts when there is no y?
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
Find the x and y intercepts of 3x-2y6?
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
Find the x and y intercept of 9x54-6y?
I believe that you need an equation to solve for the x and y intercepts.
