The shape that has a perimeter of 26 cm and an area of 36 cm² is a rectangle. To find the dimensions of the rectangle, we need to set up equations based on the given information. Let the length be L and the width be W. The perimeter formula for a rectangle is P = 2(L + W) and the area formula is A = L * W. By solving the system of equations P = 26, A = 36, we can find that the dimensions of the rectangle are length = 9 cm and width = 4 cm.
Area 42 cm2, perimeter 26 cm.
The area of an object with a perimeter of 26 centimeters
It can be 56.25 or anything less, but not more. You can't tell the area from the perimeter, and you can't tell the perimeter from the area. -- if each side is 7.5, the perimeter is 30, and the area is 56.25 -- if it's (5 by 10), the perimeter is still 30, and the area is 50 -- if it's (4 by 11), the perimeter is still 30, and the area is 44 -- if it's (3 by 12), the perimeter is still 30, and the area is 36 -- if it's (2 by 13), the perimeter is still 30, and the area is 26 -- if it's (1 by 14), the perimeter is still 30, and the area is 14
Draw the table and calculate the area of the triangle the area of a square is 36
The area of a rectangle is calculated by multiplying its length by its width. In this case, the area would be 8km x 5km = 40 square kilometers. The perimeter of a rectangle is found by adding the lengths of all four sides. For this rectangle, the perimeter would be 2(8km) + 2(5km) = 16km + 10km = 26 kilometers.
Area 42 cm2, perimeter 26 cm.
The area of an object with a perimeter of 26 centimeters
The perimeter is 10 + 3 + 10 + 3 = 26 in. The area is indeterminate because a quadrilateral is not a rigid shape and can be "squished". The area is anything between 0 and 30 sq inches.
The perimeter of a shape is the total distance around its outer boundary. For a rectangle with sides of 9 meters and 4 meters, the perimeter would be calculated as P = 2(9) + 2(4) = 18 + 8 = 26 meters. The area of a shape is the total space enclosed within its boundaries. For the same rectangle, the area would be calculated as A = 9 * 4 = 36 square meters.
The area doesn't tell you the dimensions or the perimeter. It doesn't even tell you the shape. -- Your area of 36 cm2 could be a circle with a diameter of 6.77 . (Perimeter = 21.27.) -- It could be a square with sides of 6 . (Perimeter = 24.) -- It could be rectangles that measure 1 by 36 (Perimeter = 74) 2 by 18 (Perimeter = 40) 3 by 12 (Perimeter = 30) 4 by 9 (Perimeter = 26). There are an infinite number of more rectangles that it could be, all with the same area but different perimeters.
26 cm
Area: 30 square ftIf this is just a rectangle, the perimeter around this shape is 26 feet.
Yes, but it would be very long and narrow. To get a perimeter of 30 you could have two sides that are 14 and two sides that are 1 which gives an area of 14. Conversely you could have an object with two sides that are 13 and two sides that are 2 which gives you an area of 26. Since 18 is between 14 and 26, there must be a shape between these two shapes that has area 18 and perimeter 30. You can find out exactly what those dimensions are by solving the two simultaneous equations for area and perimeter. area = width X height and perimeter = 2width + 2height knowing the area and perimeter, solve one equation for width or height and plug it into the other equation and solve.
Perimeter = 104 cmArea = 676 sq cm.
A square with a side length of 6.5 units (26/4) has an area of 42.25 square units.
Sorry- no one answer- the area will vary depending on the length of the sides.
It can be 56.25 or anything less, but not more. You can't tell the area from the perimeter, and you can't tell the perimeter from the area. -- if each side is 7.5, the perimeter is 30, and the area is 56.25 -- if it's (5 by 10), the perimeter is still 30, and the area is 50 -- if it's (4 by 11), the perimeter is still 30, and the area is 44 -- if it's (3 by 12), the perimeter is still 30, and the area is 36 -- if it's (2 by 13), the perimeter is still 30, and the area is 26 -- if it's (1 by 14), the perimeter is still 30, and the area is 14