Ah, what a delightful question! A rectangle with a perimeter of 26 units and an area of 36 square units would have dimensions of length 9 units and width 8 units. You see, by multiplying the length and width, we get the area, and by adding all the sides together, we get the perimeter. Happy little rectangles!
If it was a square, which is a rectangle, the perimeter would be 24 meters . But it was a regular rectangle than it could be a few things actually , one of them would be 26 meters . Another would be 40 meters I think .
The perimeter doesn't tell you the area. There are an infinite number of differentareas that it could have.-- If it's a circle with a perimeter of 36, then the area is 103.1324. (rounded)-- If it's a square with a perimeter of 36, then the area is 81 .-- If it's a rectangle with a perimeter of 36, then the area can be any numberthat's more than zero and less than 81 .
The shape that has a perimeter of 26 cm and an area of 36 cm² is a rectangle. To find the dimensions of the rectangle, we need to set up equations based on the given information. Let the length be L and the width be W. The perimeter formula for a rectangle is P = 2(L + W) and the area formula is A = L * W. By solving the system of equations P = 26, A = 36, we can find that the dimensions of the rectangle are length = 9 cm and width = 4 cm.
It can be 56.25 or anything less, but not more. You can't tell the area from the perimeter, and you can't tell the perimeter from the area. -- if each side is 7.5, the perimeter is 30, and the area is 56.25 -- if it's (5 by 10), the perimeter is still 30, and the area is 50 -- if it's (4 by 11), the perimeter is still 30, and the area is 44 -- if it's (3 by 12), the perimeter is still 30, and the area is 36 -- if it's (2 by 13), the perimeter is still 30, and the area is 26 -- if it's (1 by 14), the perimeter is still 30, and the area is 14
Perimeter = 2*(Length+Width) So 36 = 2*(L+4) 18 = L+4 or L = 14
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
A 4 ft by 9 ft rectangle
If it's a rectangle then:- Area = 9*4 = 36 square meters Perimeter = 9+4+9+4 = 26 meters
Perimeter is 36 mArea is 72 square m
If it was a square, which is a rectangle, the perimeter would be 24 meters . But it was a regular rectangle than it could be a few things actually , one of them would be 26 meters . Another would be 40 meters I think .
The perimeter doesn't tell you the area. There are an infinite number of differentareas that it could have.-- If it's a circle with a perimeter of 36, then the area is 103.1324. (rounded)-- If it's a square with a perimeter of 36, then the area is 81 .-- If it's a rectangle with a perimeter of 36, then the area can be any numberthat's more than zero and less than 81 .
Length = 9 Width = 9 Your rectangle is a square.
It is: 12 units in length
The shape that has a perimeter of 26 cm and an area of 36 cm² is a rectangle. To find the dimensions of the rectangle, we need to set up equations based on the given information. Let the length be L and the width be W. The perimeter formula for a rectangle is P = 2(L + W) and the area formula is A = L * W. By solving the system of equations P = 26, A = 36, we can find that the dimensions of the rectangle are length = 9 cm and width = 4 cm.
81 square feet.
It is a 3 x 15 rectangle !
18" is not a possible perimeter measurement. Assume the dimensions of the rectangle are so close to those of a square that the difference can be disregarded. This is the condition when the perimeter is at its minimum. When the rectangle measures approximately 6" x 6", its area = 36 sq ins, its perimeter = 24" For the area to remain constant then as the length increases by a factor n the width must decrease by that same factor. Area = 6n x 6/n : perimeter = 12n + 12/n :so when n = 1, Perimeter = 12 + 12 = 24 As n increases, say n = 2, Perimeter = 24 + 6 = 30 : And the perimeter continues to increase as the rectangle becomes narrower. Eventually, it will become so narrow that for diagram purposes it will appear as a straight line.