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A point Q on a segment with endpoints A (2,-1) and C (4,2) partitions the segment in a 4:1 ratio. Find Q. You must show all work to receive credit?
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How do you find the missing endpoint of a segment with an endpoint and a midpoint?
The direction of missing endpoint is the same as the direction from the known end point to the midpoint. The distance from the midpoint to the missing endpoint is the same as the distance from the known end point to the midpoint. In coordinate geometry it is simple. If the known end point is (p, q) and the mid point is (r, s) then the missing point is (2r - p, 2s - q).
Why do you choose the Q point at the centre of the load line?
When operating point is chosen at the center of the load line, faithful reproduction of the amplified signal is obtained by allowing large voltage and current. So we choose q point at the center of the loadline.
What is the sign of the y vaue of a point?
That depends on whether it's above the x-axis (Q-1 or Q-2) or below the x-axis (Q-3 or Q-4). So, based on the information in the question, it could go either way.
In the diagram below which distance represents the distance from point Q to RS?
QT (APEX)
A point Q on a segment with endpoints A (2,-1) and C (4,2) partitions the segment in a 4:1 ratio. Find Q. You must show all work to receive credit?
yor mom is fat
Which segment is a tangent segment to circle Q?
a and b
In this equation what does Q repressent?
Depends on the equation. If it is similar to: Q = m*Cp*dT then Q = energy if it is similar to A= Ao * exp (-Q/RT) then Q is the activation energy
IF the p and q are two points in the plane the perpendicular bisector of pq is the set of all points equidistant from p and q?
Yes, the perpendicular bisector of the line segment connecting points ( p ) and ( q ) is indeed the set of all points that are equidistant from both ( p ) and ( q ). This line is perpendicular to the segment ( pq ) at its midpoint, ensuring that any point on the bisector maintains equal distance to both ( p ) and ( q ). Thus, it effectively divides the segment into two equal halves while being perpendicular to it.
How do you work out and find the perpendicular bisector equation meeting the straight line segment of p q and 7p 3q?
First find the mid-point of the line segment which will be the point of intersection of the perpendicular bisector. Then find the slope or gradient of the line segment whose negative reciprocal will be the perpendicular bisector's slope or gradient. Then use y -y1 = m(x -x1) to find the equation of the perpendicular bisector. Mid-point: (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope or gradient: 3q-q/7p-p = 2q/6p = q/3p Slope of perpendicular bisector: -3p/q Equation: y -2q = -3p/q(x -4p) y = -3px/q+12p2/q+2q Multiply all terms by q to eliminate the fractions: qy = -3px+12p2+2q2 Which can be expressed in the form of: 3px+qy-12p2-2q2 = 0
How do you find the missing endpoint of a segment with an endpoint and a midpoint?
The direction of missing endpoint is the same as the direction from the known end point to the midpoint. The distance from the midpoint to the missing endpoint is the same as the distance from the known end point to the midpoint. In coordinate geometry it is simple. If the known end point is (p, q) and the mid point is (r, s) then the missing point is (2r - p, 2s - q).
How do you draw the Q point?
Q
Point b is between q and r on qr and qb equals 20 br equals 10?
This isn't a question, even. It's a statement about a line segment, QR.
How do you draw an angle MNQ?
To draw an angle MNQ, start by drawing a straight line to represent one side of the angle, which we can label as line segment MN. Next, use a protractor to measure the desired angle from point M, marking the point Q on the opposite side. Finally, draw a line from M through point Q to complete the angle MNQ.
What is the perpendicular bisector equation of a line segment with endpoints of p q and 7p 3q?
A line with slope m has a perpendicular with slope m' such that:mm' = -1→ m' = -1/mThe line segment with endpoints (p, q) and (7p, 3q) has slope:slope = change in y / change in x→ m = (3q - q)/(7p - p) = 2q/6p = q/3p→ m' = -1/m = -1/(q/3p) = -3p/qThe perpendicular bisector goes through the midpoint of the line segment which is at the mean average of the endpoints:midpoint = ((p + 7p)/2, (q + 3q)/2) = (8p/2, 4q/2) = (4p, 2q)A line through a point (X, Y) with slope M has equation:y - Y = M(x - x)→ perpendicular bisector of line segment (p, q) to (7p, 3q) has equation:y - 2q = -3p/q(x - 4p)→ y = -3px/q + 12p² + 2q→ qy = 12p²q + 2q² - 3pxAnother Answer: qy =-3px +12p^2 +2q^2
What is the notation for the length of the segment between P and Q?
pq
How do humans fit in the water cycle?
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