What points are on the line y plus .5x?

Answer 1

The equation y + 0.5x represents a line in slope-intercept form, where the coefficient of x is 0.5 (representing the slope) and the y-intercept is 0 (since there is no constant term). To find points on this line, you can substitute different values of x and solve for y.

Here are a few examples of points on the line:

1.When x = 0:

y + 0.5(0) = 0

y = 0

Point: (0, 0)

2.When x = 2:

y + 0.5(2) = 0

y + 1 = 0

y = -1

Point: (2, -1)

3.When x = -4:

y + 0.5(-4) = 0

y - 2 = 0

y = 2

Point: (-4, 2)

You can continue to substitute different values of x to find more points on the line. Alternatively, you can use the slope-intercept form to determine additional points by choosing any value for x and calculating the corresponding value for y using the equation y = -0.5x. This will give you an infinite number of points that lie on the line y + 0.5x.

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Answer 2

The points on the line y + .5x are all the points of the form (x, y) that satisfy the equation y + .5x = 0.

This is a standard form linear equation, where y is the dependent variable and x is the independent variable. The equation y + .5x = 0 can be rewritten as y = -.5x. This is the slope-intercept form of the equation of a line, where the slope of the line is -.5 and the y-intercept is 0.

Thus, the line y + .5x is a line with a slope of -.5 and a y-intercept of 0. All the points on this line have an x-coordinate that satisfies the equation y + .5x = 0.

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Answer 3

y + 0.5x is not an equation, it is simply an expression. Unless it is an equation, it is not a line and so has no points on it.

Answer 4

Every point along the line y=x has the identical x and y coordinate values, which are x=a and y-a. As a result, the solution to the given linear equation must take the form (a,a).