The rectangle is 99 cm2 in area. Here's how we got it. The rectangle has length (l) and width (w). A length and a length and a width and a width all added up equals 40 cm. And l is 2 cm longer than w, so l = w + 2. If we add w + 2 and w + 2 (the two lengths) and w and w, we get 40 cm. That's 4w + 4 cm = 40 cm. 4w = 36 cm, and w = 9 cm. The width is 9 cm, and the length is 2 cm more or 11 cm. The rectangle is 9 cm by 11 cm, and its area is 9 x 11 cm2, or 99 cm2.
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
21cm3
The perimeter of a rectangle is found by the following formula: (Length x 2) + (Width x 2) or Length + Length + Width + Width.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the width equals 14 cm. and the length equals 31 cm.
21cm3
The perimeter of a rectangle is found by the following formula: (Length x 2) + (Width x 2) or Length + Length + Width + Width.
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle