Slope: -5
Points: (6, 3)
Equation: y = -5x+33
If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90
Point: (2, -1) Slope: -5 Equation: y = -5x+9
y=2x+13
y = 2x - 1
It is: y = 2x-6
Choose the equation of the line that contains the points (1, -1) and (2, -2).
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33
Slope: -3 Point: (4, -5) Equation: y = -3x+7
If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5