It is 0.6046 : 1 (approx).
In a right angle triangle divide the opposite by the hypotenuse to find the sine ratio.
To create three different drawings showing a number of circles and triangles in which the ratio is 2:3 you can: Start with an equilateral triangle, draw a circle inside it, draw an equilateral triangle inside the circle, draw a circle in the triangle and then draw an equilateral tiangle in the smallest circle. Or, you could draw 3 triangles and 2 circles in a line. Or, you could draw 3 triangles on a line with 2 circles between them.
An equilateral triangle hasn't a hypotenuse; hypotenuse means the side opposite the right angle in a right triangle. An equilateral triangle has no right angles; rather all three of its angles measure 60 degrees. Knowing the length of the hypotenuse of a right triangle does not give enough information to determine the triangle's height. But the length of a side (which is the same for every side) of an equilateral triangle is enough information from which to calculate the height of that triangle. The first way is simply to use the formula that has been developed for this purpose: height = (length X sqrt(3)) / 2. But you can also use the geometry of right triangles to solve for the height. That is because you can bisect the triangle with a vertical line from the top vertex to the center of the base. The length of that line, which splits the equilateral triangle into two right triangles, is the height of the equilateral triangle. We know a lot about each right triangle formed by bisecting the equilateral triangle: * - The hypotenuse length is the length of the equilateral triangle's side. * - The base length is half the length of the hypotenuse. * - The angle opposite the hypotenuse is 90 degrees. * - The angle opposite the vertical is 60 degrees (the measure of every angle of any equilateral triangle). * - The angle opposite the base is 30 degrees (half of the bisected 60-degree angle). * - (Note that the sum of the angles does equal 180 degrees, as it must.) Now to solve for the height of a right triangle. There are a few ways. For labeling, let's let h=height of the equilateral triangle and the vertical side of the right triangle; A=every angle of the equilateral triangle (each 60o); s=side length of any side of the equilateral triangle and thus the hypotenuse of the right triangle. Since the sine of an angle of a right triangle is equal to the ratio of the opposite side divided by the hypotenuse, we can write that sin(A) = h/s. Solving for h, we get h=sin(A)/s. With trig tables you can now easily find the height.
The answer to the question depends on what the ratio is between: side length and area, or lengths of base and height, or interior and exterior angles. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
If an equilateral triangle and a square have equal perimeters, then the ratio of the area of the triangle to the area of the square is 1:3.
It is 0.6046 : 1 (approx).
Two to one, with the larger segment being towards the vertices of the triangle.
The centroid of a triangle is the point of intersection of the medians and divides each median in the ratio 2:1
TriangleA a=90.6 TriangleB a=188.9 90.6/188.9 = .48 I think this is right, not completely sure though.
Divide the length of a side of one triangle by the length of the corresponding side of the other triangle.
Length of a side of an equilateral triangle : Perimeter = 1 : 3 For example, if the length of the sides of an equilateral triangle were 5cm each, then perimeter would be three times that much - 15cm. 5 : 15 is the same as 1 : 3 when simplified. Length of a side of an equilateral triangle : Perimeter = 1 : 3 For example, if the length of the sides of an equilateral triangle were 5cm each, then perimeter would be three times that much - 15cm. 5 : 15 is the same as 1 : 3 when simplified.
The centroid of a triangle is the point of intersection of its three medians. Each median of a triangle connects a vertex to the midpoint of the opposite side. The centroid divides each median into two segments with a ratio of 2:1, closer to the vertex.
It is an equilateral triangle
In a right angle triangle divide the opposite by the hypotenuse to find the sine ratio.
To create three different drawings showing a number of circles and triangles in which the ratio is 2:3 you can: Start with an equilateral triangle, draw a circle inside it, draw an equilateral triangle inside the circle, draw a circle in the triangle and then draw an equilateral tiangle in the smallest circle. Or, you could draw 3 triangles and 2 circles in a line. Or, you could draw 3 triangles on a line with 2 circles between them.
Two triangles are similar if: 1) 3 angles of 1 triangle are the same as 3 angles of the other or 2) 3 pairs of corresponding sides are in the same ratio or 3) An angle of 1 triangle is the same as the angle of the other triangle and the sides containing these angles are in the same ratio. So if they are both equilateral, then they both have three 60 degree angles since equilateral triangles are equiangular as well. Then number 1 above tell us by AAA, they are similar.