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How is geometric constraints different from numeric constraints?
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What is A-B squared?
(a-b)^2 doesn't have a numeric value since there are no numbers associated with it, but you can definitely expand it, as it represents a formula, instead of an actual numeric expression.(a-b)(a-b)= a^2-ab-ab+b^2= a^2-2ab+b^2 (which is actually the rule for expanding!)
What is a term that refers to the degree of exactness?
A degree of exactness of a numeric integration formula is the highest number for which all polynomials of degree equal or less than the number, satisfy the condition that the formula for them is precise (0 error)
Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5 in whose upper base is a square with a side 3 in?
The Answers community requested more information for this question. Please edit your question to include more context. I order to calculate the volume it is necessary to have some information of the height. This can be the height of the frustum, the eight of the whole pyramid, the angle of the sloped faces.
How do you calculate the intersection point of a line and a circle given a line starting point Lx Ly and an angle from north a the circle location Cx Cy and its radius r?
The angle of the line is a degrees from North so the angle from East is (90 - a) degrees. Therefore gradient of the line is tan(90-a) = 1/tan(a).Then any point on the line has coordinates (x, y) = (Lx + ksina, Ly + kcosa).The coordinates of any point on the circle satisfy (x - Cx)2 + (y - Cy)2 = r2The points of intersection must satisfy both equations so that:(Lx + ksina - Cx)2 + (Ly + kcosa - Cy)2 = r2This equation needs to be solved for k - everything else has a known numeric value. Since it is a quadratic, in k, there will be 0, 1 or 2 solutions for k depending on the line not intersecting the circle at all, being tangent to it and going through the circle.The angle of the line is a degrees from North so the angle from East is (90 - a) degrees. Therefore gradient of the line is tan(90-a) = 1/tan(a).Then any point on the line has coordinates (x, y) = (Lx + ksina, Ly + kcosa).The coordinates of any point on the circle satisfy (x - Cx)2 + (y - Cy)2 = r2The points of intersection must satisfy both equations so that:(Lx + ksina - Cx)2 + (Ly + kcosa - Cy)2 = r2This equation needs to be solved for k - everything else has a known numeric value. Since it is a quadratic, in k, there will be 0, 1 or 2 solutions for k depending on the line not intersecting the circle at all, being tangent to it and going through the circle.The angle of the line is a degrees from North so the angle from East is (90 - a) degrees. Therefore gradient of the line is tan(90-a) = 1/tan(a).Then any point on the line has coordinates (x, y) = (Lx + ksina, Ly + kcosa).The coordinates of any point on the circle satisfy (x - Cx)2 + (y - Cy)2 = r2The points of intersection must satisfy both equations so that:(Lx + ksina - Cx)2 + (Ly + kcosa - Cy)2 = r2This equation needs to be solved for k - everything else has a known numeric value. Since it is a quadratic, in k, there will be 0, 1 or 2 solutions for k depending on the line not intersecting the circle at all, being tangent to it and going through the circle.The angle of the line is a degrees from North so the angle from East is (90 - a) degrees. Therefore gradient of the line is tan(90-a) = 1/tan(a).Then any point on the line has coordinates (x, y) = (Lx + ksina, Ly + kcosa).The coordinates of any point on the circle satisfy (x - Cx)2 + (y - Cy)2 = r2The points of intersection must satisfy both equations so that:(Lx + ksina - Cx)2 + (Ly + kcosa - Cy)2 = r2This equation needs to be solved for k - everything else has a known numeric value. Since it is a quadratic, in k, there will be 0, 1 or 2 solutions for k depending on the line not intersecting the circle at all, being tangent to it and going through the circle.
