The formula for perimeter is P=2XL+2XW which is Perimeter = 2 X length + 2 X Width. We want to replace L and W with the the numbers 9 and 5. I don't know which is which but lets say the 9 is the length and 5 is the width. So the new number sentence would be P=2X9+2X5. So now it's time to solve. 2X9=18. 2X5=10. 10+18=28. Your perimeter would be 28cm. Hope this helped! :)
9cm+9cm+5cm+5cm=
Perimeter = 6cm + 6cm + 9cm + 9cm = 30cm
The answer is, you can draw a rectangle with these measurements: 6cm and 9cm 5cm and 10cm 7cm and 8cm
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
63 cmPerimeter = 2 x (Length + Width) = 2 x (9cm + 7cm) = 2 x 16cm = 32cm
if one length is 9cm, the other length must be 6cm to make an area of 54cm. hence the perimeter is 9+9+6+6 = 30cm
9cm + 5cm + 9cm + 5cm = 28cm
Perimeter = 6cm + 6cm + 9cm + 9cm = 30cm
If you're talking about a five sided figure, just add up your figures.
Assuming no fractional dimensions, least possible area would be a rectangle measuring 1cm x 9cm. Area increases to a maximum of 25 sq cm when shape is square, ie 5cm x 5cm.
The answer is, you can draw a rectangle with these measurements: 6cm and 9cm 5cm and 10cm 7cm and 8cm
28 cm
18.5cmImproved Answer:-Perimeter = 9+9.5+9+9.5 = 37cm
24 cm is.
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
0cm
it is 81cm