An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.
Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
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perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
Infinite amounts.
There are infinitely many possible rectangles. Let A be ANY number in the range (0,6] and let B = 12-A. Then a rectangle with width A and length B will have a perimeter of 2*(A+B) = 2*12 = 24 units. Since A is ANY number in the interval (0,6], there are infinitely many possible values for A and so infinitely many answers to the question.
Rectangles and squares both have 4 corners.
2 triangles and 3 rectangles(: