perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
Infinite amounts.
There are infinitely many possible rectangles. Let A be ANY number in the range (0,6] and let B = 12-A. Then a rectangle with width A and length B will have a perimeter of 2*(A+B) = 2*12 = 24 units. Since A is ANY number in the interval (0,6], there are infinitely many possible values for A and so infinitely many answers to the question.
Rectangles and squares both have 4 corners.
2 triangles and 3 rectangles(:
There would be an infinite number of rectangles possible
Depends what you are drawing on.
There is an infinite number that can have that perimeter
thare is only 1 differint rectangles
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
15
the answer is 12
13
Infinite amounts.
As many as you want, if they are small enough!
I don't understand why there are so many questions about rectangles' perimeter. You just add the length and the width and double your answer....
The only one I can think of is a square, where Length=Width=4.