Assuming that you are not using angles, but only ratios I have the following:
Your answer is 30 ft
Calculations:
5 ft : 3f & 4 in (40in)
20 * 12 = 240 in
240 / 40 = 6
6 * 5 = 30 ft
That depends on the height of the yardstick whose height has not been given.
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
Using Pythagoras' theorem it is 30 feet
Answer is 14 feet
Tan60= 25/Height. Height = 25/Tan60 = 14.43
A 1 foot shadow I think.
That depends on the height of the yardstick whose height has not been given.
Using trigonometry its height is 12 feet
2
If the shadow of a 6-ft person is 4-ft long, then in this place at this moment, all shadowsare 2/3 the length of the vertical object that casts them.The 9-ft shadow therefore 2/3 the height of the tree. The height is (9)/(2/3) = (9 x 3/2) = 13.5-ft.-----------------------------------------(9/4)*6=13.5 ft.
It works out as 12 feet and 4 inches in height
Shadow lengths are proportional to the heights of objects casting the shadows. Therefore, calling the shadow length l, the height h, and the proportionality constant k, l = kh. (The intercept is 0 because an object with no height casts no shadow.) Therefore, in this instance k = l/h = 6/3 or 8/4 = 2. then l(6) = 2 X 6 = 12 feet.
15 feet high
121.3yd
63 feet
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
The height of a boy that casts a 4 foot long shadow depends on the angle of the sun. A tangent can be used to calculate his height if we know the angle of the sun using the equation: Height = shadow length x tangent of the angle of the sun. Using a calculator, it is easy to get the value of the tangent for any angle and then complete the equation.