Assuming that you are not using angles, but only ratios I have the following:
Your answer is 30 ft
Calculations:
5 ft : 3f & 4 in (40in)
20 * 12 = 240 in
240 / 40 = 6
6 * 5 = 30 ft
A baker bakes 1134 laaves of bread in 27 day how many loaves of bread did he bake in on day
That depends on the height of the yardstick whose height has not been given.
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
Using Pythagoras' theorem it is 30 feet
Answer is 14 feet
Tan60= 25/Height. Height = 25/Tan60 = 14.43
A 1 foot shadow I think.
That depends on the height of the yardstick whose height has not been given.
Using trigonometry its height is 12 feet
2
If the shadow of a 6-ft person is 4-ft long, then in this place at this moment, all shadowsare 2/3 the length of the vertical object that casts them.The 9-ft shadow therefore 2/3 the height of the tree. The height is (9)/(2/3) = (9 x 3/2) = 13.5-ft.-----------------------------------------(9/4)*6=13.5 ft.
It works out as 12 feet and 4 inches in height
Shadow lengths are proportional to the heights of objects casting the shadows. Therefore, calling the shadow length l, the height h, and the proportionality constant k, l = kh. (The intercept is 0 because an object with no height casts no shadow.) Therefore, in this instance k = l/h = 6/3 or 8/4 = 2. then l(6) = 2 X 6 = 12 feet.
15 feet high
121.3yd
63 feet
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
The height of a boy that casts a 4 foot long shadow depends on the angle of the sun. A tangent can be used to calculate his height if we know the angle of the sun using the equation: Height = shadow length x tangent of the angle of the sun. Using a calculator, it is easy to get the value of the tangent for any angle and then complete the equation.