Using Pythagoras' theorem it is 30 feet
12ft
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
Answer is 14 feet
That depends on the height of the yardstick whose height has not been given.
tan-1(40/30) = 53.13° Therefore, the sun is at a 53.13° angle of elevation.
Assuming that you are not using angles, but only ratios I have the following:Your answer is 30 ftCalculations:5 ft : 3f & 4 in (40in)20 * 12 = 240 in240 / 40 = 66 * 5 = 30 ft
We can solve this problem using a ratio. Since a 6 foot man casts a 4 foot shadow we can write this ratio as 6:4. If we reduce this ratio we get 3:2. Now we're stating that for every 3 feet of height, the shadow cast will be 2 feet.Now we can work our problem out using a small table:3 feet of flag pole = 2 feet of shadow6 feet of flag pole = 4 feet of shadow9 feet of flag pole = 6 feet of shadow12 feet of flag pole = 8 feet of shadow15 feet of flag pole = 10 feet of shadow18 feet of flag pole = 12 feet of shadowTherefore an 18 foot flag pole will cast a 12 foot shadow at the same time that a 6 foot man casts a 4 foot shadow.
A 1 foot shadow I think.
63 feet
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
2
15 feet high
Using trigonometry its height is 12 feet
27.3 feet
It works out as 3.75 feet
17.45 feet.
4 is to 6 as 5 is to X. 4/6 = 5/X. X = 7.5 feet.
5.5/8 = x/20 x=5.5*20/8 = 13.75 feet