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Where is the center of the circle given by the equation (x 5)2 (y - 3)2 25?
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∙ 8y ago
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If the first bracket contains x + 5 then the abscissa of the centre is -5 and so the centre is (-5, 2), and if the first bracket contains x - 5 then the abscissa of the centre is 5 and so the centre is (5, 2).
Wiki User
∙ 8y ago
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What is the equation of the circle that touches the x axis when its center is at 2 5?
Center of circle: (2, 5) Point of contact with the x axis: (2, 0) Distance from (2, 5) to (2, 0) equals 5 which is the radius of the circle Equation of the circle: (x-2)^2 +(y-5)^2 = 25
This circle is centered at the origin and the length of its radius is 5 What is the equation of the circle?
x2 + y2 = 25
This circle is centered at the origin and the length of its radius is 5 What is the circle's equation?
x2 + y2 = 25
What is the equation of a circle centered at the origin with a radius of 5cm?
x2 + y2 = 25 A circle with centre (xo, yo) and radius r has equation: (x - xo)2 + (y - yo)2 = r2 So with centre the origin (0, 0) and radius 5 cm, the circle has equation: (x - 0)2 + (y - 0)2 = 52 ⇒ x2 + y2 = 25
How do you write an equation for a circle graph with center at -4 2 and radius 5?
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
Is the center of the circle given by the equation x plus 2 2 plus y - 52 equals 25?
At the center, (x, y) = (-2, 5)
Is the center of the circle given by the equation x plus 2 2 plus y - 5 2 equals 25?
At the center, (x, y) = (-2, 5)
What is the center of the circle given by the equation x plus 2 2 plus y - 5 2 equals 25?
At the center, (x, y) = (-2, 5)
Where is the center of the circle given by the equation x plus 5 2 plus y - 3 2 equals 25?
(-5, 3)
Where is the center of the circle given by the equation x - 8 2 plus y plus 8 2 equals 25?
(8,-8)
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 equals 25 Enter your answer as an ordered pair?
It's at the point ( -5, 3 ) The general formula of a circle is given by the equation: ( x - h )2 + ( y - k )2 = r2 Where the point ( h, k ) is the center of the circle, and r is the radius of the circle. In the equation ( x + 5 )2 + ( y - 3 )2 = 25 The first group of terms isn't subtracted. Rather than x + 5, this is actually x - -5. The center of the circle, then, is the point ( -5, 3 )
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 squared equals 25?
The centre is (-5, 3)
What is the center and radius of a circle defined by the equation (x-4)^2 +(y-5)^2=25?
d
What is the equation of the circle that touches the x axis when its center is at 2 5?
Center of circle: (2, 5) Point of contact with the x axis: (2, 0) Distance from (2, 5) to (2, 0) equals 5 which is the radius of the circle Equation of the circle: (x-2)^2 +(y-5)^2 = 25
What is the equation of a circle with center (8 6) and radius 5?
(x - 8)^2 + (y - 6)^2 = 25
What is the equation of the circle that has a center at (-3 1) and a radius of 5?
It is: (x+3)^2+(y-1)^2 = 25
Where is the center of the circle given by the equation x plus 5 times 2 plus y - 3 times 2 equals 25 in an ordered pair?
Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.
