because if you take the diameter and wrap it around the circle it will only go around it 3 times and a little more, therefore you get 3.14159...
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9 √(2/pi) We start with the formulas for surface area (4 pi r^2) and volume (4/3 pi r^3). If 4 pi r^2 = 18, then r = 3/√(2 pi); plug that into the formula for volume and we get 9 √(2/pi) as the answer.
Cube: 216 m^3 Volume of cube=s^3 s=6 6^3=216 Hemisphere: 18pi m^3 ~ 56.5486678 m^3 sphere: (4/3)pi(r^3) hemisphere: ((4/3)pi(r^3))/2=(4/6)pi(r^2)=(2/3)pi(r^3) d=6 r=3 (2/3)pi(3^3)=(2/3)pi(27)=(54/3)pi=18pi
~14.1372 V=(4/3)pi r^3 V=(4/3)pi (1.5)^3=(4/3)pi 3.375=4.5pi~14.1372
Yes if the diameter is rational. But it need not be if the diameter is irrational. If the diameter is 3/pi units, for example, then the circumference will be (3/pi)*pi = 3 units.
c = pi * d 90in = pi * 30in pi = 3 .. which is incorrect