because if you take the diameter and wrap it around the circle it will only go around it 3 times and a little more, therefore you get 3.14159...
9 √(2/pi) We start with the formulas for surface area (4 pi r^2) and volume (4/3 pi r^3). If 4 pi r^2 = 18, then r = 3/√(2 pi); plug that into the formula for volume and we get 9 √(2/pi) as the answer.
Cube: 216 m^3 Volume of cube=s^3 s=6 6^3=216 Hemisphere: 18pi m^3 ~ 56.5486678 m^3 sphere: (4/3)pi(r^3) hemisphere: ((4/3)pi(r^3))/2=(4/6)pi(r^2)=(2/3)pi(r^3) d=6 r=3 (2/3)pi(3^3)=(2/3)pi(27)=(54/3)pi=18pi
~14.1372 V=(4/3)pi r^3 V=(4/3)pi (1.5)^3=(4/3)pi 3.375=4.5pi~14.1372
Yes if the diameter is rational. But it need not be if the diameter is irrational. If the diameter is 3/pi units, for example, then the circumference will be (3/pi)*pi = 3 units.
c = pi * d 90in = pi * 30in pi = 3 .. which is incorrect
I know what it is
9 √(2/pi) We start with the formulas for surface area (4 pi r^2) and volume (4/3 pi r^3). If 4 pi r^2 = 18, then r = 3/√(2 pi); plug that into the formula for volume and we get 9 √(2/pi) as the answer.
9
The 80888840 the digit after the decimal place is a 5. If you start counting from the 3 (of 3.1415...) then it is a 3.
[pi^(1/3)]^2 * pi = pi^(2/3) * pi = pi^(5/3) The answer is the cubic root of pi to the fifth power.
18pi m^3 ~ 56.5486678 m^3 sphere: (4/3)pi(r^3) hemisphere: ((4/3)pi(r^3))/2=(4/6)pi(r^2)=(2/3)pi(r^3) d=6 r=3 (2/3)pi(3^3)=(2/3)pi(27)=(54/3)pi=18pi
(pi + pi + pi) = 3 pi = roughly 9.4248 (rounded) Well, if you use the common shortened version of pi which is 3.14 and add that 3 times, you get 9.42.
1706
Volume of a sphere = 4/3 pi R3V = (4/3) (pi) (2)3 = 8/3 pi = 8.3776(rounded)
No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3
11pi/12 = pi - pi/12 cos(11pi/12) = cos(pi - pi/12) cos(a-b) = cos(a)cos(b)+sin(a)sin(b) cos(pi -pi/12) = cos(pi)cos(pi/12) + sin(pi)sin(pi/12) sin(pi)=0 cos(pi)=-1 Therefore, cos(pi -pi/12) = -cos(pi/12) pi/12=pi/3 -pi/4 cos(pi/12) = cos(pi/3 - pi/4) = cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) cos(pi/3)=1/2 sin(pi/3)=sqrt(3)/2 cos(pi/4)= sqrt(2)/2 sin(pi/4) = sqrt(2)/2 cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) = (1/2)(sqrt(2)/2 ) + (sqrt(3)/2)( sqrt(2)/2) = sqrt(2)/4 + sqrt(6) /4 = [sqrt(2)+sqrt(6)] /4 Therefore, cos(pi/12) = (sqrt(2)+sqrt(6))/4 -cos(pi/12) = -(sqrt(2)+sqrt(6))/4 cos(11pi/12) = -(sqrt(2)+sqrt(6))/4
Yes