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because if you take the diameter and wrap it around the circle it will only go around it 3 times and a little more, therefore you get 3.14159...

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what are the first 25 digits of pi not including the 3. at the start?

I know what it is


A sphere has a surface area of 18 square centimeters. What is the volume of a sphere?

9 √(2/pi) We start with the formulas for surface area (4 pi r^2) and volume (4/3 pi r^3). If 4 pi r^2 = 18, then r = 3/√(2 pi); plug that into the formula for volume and we get 9 √(2/pi) as the answer.


What is pi times 3 divided by 3?

9


What is the 80888840 place of PI?

The 80888840 the digit after the decimal place is a 5. If you start counting from the 3 (of 3.1415...) then it is a 3.


What is the cubic root of pi squared multiplied by pi?

[pi^(1/3)]^2 * pi = pi^(2/3) * pi = pi^(5/3) The answer is the cubic root of pi to the fifth power.


Coterminal with 3pi2?

To find an angle that is coterminal with ( \frac{3\pi}{2} ), you can add or subtract multiples of ( 2\pi ). For example, ( \frac{3\pi}{2} + 2\pi = \frac{3\pi}{2} + \frac{4\pi}{2} = \frac{7\pi}{2} ) is coterminal with ( \frac{3\pi}{2} ). Similarly, subtracting ( 2\pi ) gives ( \frac{3\pi}{2} - 2\pi = \frac{3\pi}{2} - \frac{4\pi}{2} = -\frac{\pi}{2} ), which is also coterminal.


What is the volume of a hemisphere with a diameter of 6 meters?

18pi m^3 ~ 56.5486678 m^3 sphere: (4/3)pi(r^3) hemisphere: ((4/3)pi(r^3))/2=(4/6)pi(r^2)=(2/3)pi(r^3) d=6 r=3 (2/3)pi(3^3)=(2/3)pi(27)=(54/3)pi=18pi


What is pi plus pi plus pi?

(pi + pi + pi) = 3 pi = roughly 9.4248 (rounded) Well, if you use the common shortened version of pi which is 3.14 and add that 3 times, you get 9.42.


In what year did the English start using the symbol of pi for pi?

1706


What is the volume of a sphere with a radius of 2 without the pi?

Volume of a sphere = 4/3 pi R3V = (4/3) (pi) (2)3 = 8/3 pi = 8.3776(rounded)


Is the volume formula universal for all the figures?

No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3


3 plus pi equals pi plus 3?

Yes