9 √(2/pi) We start with the formulas for surface area (4 pi r^2) and volume (4/3 pi r^3). If 4 pi r^2 = 18, then r = 3/√(2 pi); plug that into the formula for volume and we get 9 √(2/pi) as the answer.
Cube: 216 m^3 Volume of cube=s^3 s=6 6^3=216 Hemisphere: 18pi m^3 ~ 56.5486678 m^3 sphere: (4/3)pi(r^3) hemisphere: ((4/3)pi(r^3))/2=(4/6)pi(r^2)=(2/3)pi(r^3) d=6 r=3 (2/3)pi(3^3)=(2/3)pi(27)=(54/3)pi=18pi
~14.1372 V=(4/3)pi r^3 V=(4/3)pi (1.5)^3=(4/3)pi 3.375=4.5pi~14.1372
Yes if the diameter is rational. But it need not be if the diameter is irrational. If the diameter is 3/pi units, for example, then the circumference will be (3/pi)*pi = 3 units.
Volume of Hemisphere = 2/3 * Pi * (radius)^3 Volume of Cone = 1/3 * Pi * (radius)^2 * height where Pi = 22/7 (approx)
I know what it is
9 √(2/pi) We start with the formulas for surface area (4 pi r^2) and volume (4/3 pi r^3). If 4 pi r^2 = 18, then r = 3/√(2 pi); plug that into the formula for volume and we get 9 √(2/pi) as the answer.
9
The 80888840 the digit after the decimal place is a 5. If you start counting from the 3 (of 3.1415...) then it is a 3.
[pi^(1/3)]^2 * pi = pi^(2/3) * pi = pi^(5/3) The answer is the cubic root of pi to the fifth power.
18pi m^3 ~ 56.5486678 m^3 sphere: (4/3)pi(r^3) hemisphere: ((4/3)pi(r^3))/2=(4/6)pi(r^2)=(2/3)pi(r^3) d=6 r=3 (2/3)pi(3^3)=(2/3)pi(27)=(54/3)pi=18pi
(pi + pi + pi) = 3 pi = roughly 9.4248 (rounded) Well, if you use the common shortened version of pi which is 3.14 and add that 3 times, you get 9.42.
1706
Volume of a sphere = 4/3 pi R3V = (4/3) (pi) (2)3 = 8/3 pi = 8.3776(rounded)
No, the volume formula is not universal for all figures. Different shapes and objects have different formulas to calculate their volume based on their unique dimensions and properties. Each shape requires its own specific formula to accurately determine its volume.
Yes
11pi/12 = pi - pi/12 cos(11pi/12) = cos(pi - pi/12) cos(a-b) = cos(a)cos(b)+sin(a)sin(b) cos(pi -pi/12) = cos(pi)cos(pi/12) + sin(pi)sin(pi/12) sin(pi)=0 cos(pi)=-1 Therefore, cos(pi -pi/12) = -cos(pi/12) pi/12=pi/3 -pi/4 cos(pi/12) = cos(pi/3 - pi/4) = cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) cos(pi/3)=1/2 sin(pi/3)=sqrt(3)/2 cos(pi/4)= sqrt(2)/2 sin(pi/4) = sqrt(2)/2 cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) = (1/2)(sqrt(2)/2 ) + (sqrt(3)/2)( sqrt(2)/2) = sqrt(2)/4 + sqrt(6) /4 = [sqrt(2)+sqrt(6)] /4 Therefore, cos(pi/12) = (sqrt(2)+sqrt(6))/4 -cos(pi/12) = -(sqrt(2)+sqrt(6))/4 cos(11pi/12) = -(sqrt(2)+sqrt(6))/4