Wiki User
∙ 14y agoif P(A)>0 then P(B'|A)=1-P(B|A)
so P(A intersect B')=P(A)P(B'|A)=P(A)[1-P(B|A)]
=P(A)[1-P(B)]
=P(A)P(B')
the definition of independent events is if P(A intersect B')=P(A)P(B')
that is the proof
Wiki User
∙ 14y agoAdlai Stevenson (Democratic Party) and Walter B. Jones (Independent)
Mexico was becoming independent
A-America B-boycott C-civil rights
Operation Just Cause 1989; arrest of Manual Noriega, leader of Panama.
At one point Ben Franklin made a political cartoon in his newspaper that was the chopped body of a snake each piece representing one of the colonies and b elow it said join or die. The colonies wound up not joining for fear of being controled by someone else. ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ That was the beginning, but they became independent from British and informed each other of important events. :)
Yes.
Given two events, A and B, Pr(A and B) = Pr(A)*Pr(B) if A and B are independent and Pr(A and B) = Pr(A | B)*Pr(B) if they are not.
p(A and B) = p(A) x p(B) for 2 independent events p(A and B and ...N) = p(A) x p(B) x p(C) x ...x p(N) In words, if these are all independent events, find the individual probabilities if each and multiply them all together.
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when the occurance of an event B is not affected by the occurance of event A than we can say that these events are not dependent with each other
the circles do not overlap at all.
first prove *: if A intersect B is independent, then A intersect B' is independent. (this is on wiki answers) P(A' intersect B') = P(B')P(A'|B') by definition = P(B')[1-P(A|B')] since 1 = P(A) + P(A') = P(B')[1 - P(A)] from the first proof * = P(B')P(A') since 1 = P(A) + P(A') conclude with P(A' intersect B') = P(B')P(A') and is therefore independent by definition. ***note*** i am a student in my first semester of probability so this may be incorrect, but i used the first proof* so i figured i would proof this one to kinda "give back".
P(A given B)*P(B)=P(A and B), where event A is dependent on event B. Finding the probability of an independent event really depends on the situation (dart throwing, coin flipping, even Schrodinger's cat...).
If two events are disjoint, they cannot occur at the same time. For example, if you flip a coin, you cannot get heads AND tails. Since A and B are disjoint, P(A and B) = 0 If A and B were independent, then P(A and B) = 0.4*0.5=0.2. For example, the chances you throw a dice and it lands on 1 AND the chances you flip a coin and it land on heads. These events are independent...the outcome of one event does not affect the outcome of the other.
apex XD 0.140.14
Concurrent independent events or simultaneous independent events
If the probability of A is p1 and probability of B is p2 where A and B are independent events or outcomes, then the probability of both A and B occurring is p1 x p2. See related link for examples.