5ft+5ft+6ft+6ft+8ft=30ft
red Q, red Q, black Q, black Q, J, 6, 7, 3, K, 2, 5, 2, 5, J, 7, K, 6, 7, 3, K, 6, 7, 3, K, 2, 5, 10, 10, 10, 10, J, 4, 4, 8, 8, 8, 4, 9, 9, 9, 9, 8, A, A, A, A, "What The Hell", J, 2, 3, 4, 5, 6 (2-6 need to be spades)
IH 304 V8 Firing Order1-8-4-3-6-5-7-2 (Timed on #8) Or as some prefer, 8-4-3-6-5-7-2-1
Sea explorer Matthew Flinders used several ships, as listed below.The vessel in which Flinders circumnavigated Australia, The Investigator, had the following dimensions:Length - 100 feet 6 inches, or 30.63mBeam - 28 ft 6 in, or 8.69mDraught - 15 ft, or 4.6mWeight - 334 tonsWhen Flinders travelled north along the east coast, he captained the Lady Nelson. Dimensions were:Length - 52 feet 6 inches, or 16mBeam - 17 ft 6 in, or 5.33mDraught - 6 ft, or 1.8mWhen Flinders and Bass circumnavigated Tasmania (Van Diemen's Land), they were in the Tom Thumb, which was very small - only about 8 ft in length.
9-8+6-5-1 is your answer, sir.
For boys its 4feet to 4feet6 super short 4feet7 to 4 feet 9 very short 4 feet 11 to 5 feet 2 short and short 5 feet 3 to 5 feet 6 short 5 feet 7 to 5 feet 8 under average 5 feet 9 average 5 feet 10 to 6 feet 2 getting tall 6 feet 3 to 6 feet 6 tall 6 feet 7 to 6 feet 8 tall and tall 6 feet 9 to 6 feet 11 very tall 7 feet to 8 feet giant . For girls 5 feet 4 avarages anything over is considered tall for girls anything shorter then 5 feet 4 for girls considered short for em
33 feet
2 x (8 + 6), ie 28 ft.
8 ft.
5 ft + 20 inches = 6 ft + 8 inches.5 ft + 20 inches = 6 ft + 8 inches.5 ft + 20 inches = 6 ft + 8 inches.5 ft + 20 inches = 6 ft + 8 inches.
It is: 5*8 = 40 feet
It is 2*(5*8 + 8*6 + 6*5) = 2*(40 + 48 + 30) = 2*118 = 236 square feet.
Perimeter = (10.25 + 8 + 10.25 + 8) = 36.5 ft Area = (10.25 x 8) = 82 square ft
Perimeter = 2*(width + length) = 2*(8/12 + 2)feet = 2*(2/3 + 2) feet = 2*8/3 ft = 16/3 ft or 51/3 ft = 5 ft 4 inches
yes. add all sides together to find the perimeter. 7+8+10=25.
32 ft.
40 ft.
The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.