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What is the slope of the line that contains the points -32 23 and -32 -19?
It has no slope.
What is the slope of the line that contains the points (-22) and (32)?
Points: (-1, -1) and (-3, 2) Slope: -3/2
What is the equation of the line that passes through the points (12 8) and (17 16)?
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
What is the slope of a line that contains points (-1-1) and (-32)?
Points: (-1, -1) and (-3, 2) Slope: -3/2
What does 32-10x plus 7y equal?
If you mean: 32-10x+7y = 0 then as a straight line equation it is 7y = 10x-32
What is the equation for (-1-4)and(32)?
If you mean points of: (-1, -4) and (3, 2) Slope: 3/2 Equation works out as: 2y = 3x-5
Line D is parallel to the line y-5 and passes through 32 Is there enough information to make a rule and equation?
yes there is it would be 10!!
What is the slope of the line perpendicular to -4x plus 3y equals -32?
To find the slope of the line perpendicular to the given equation, we first need to determine the slope of the original line. The equation (-4x + 3y = -32) can be rearranged into slope-intercept form (y = mx + b). Solving for (y), we get (3y = 4x - 32) or (y = \frac{4}{3}x - \frac{32}{3}), which has a slope of (\frac{4}{3}). The slope of a line perpendicular to this would be the negative reciprocal, which is (-\frac{3}{4}).
Which of the following shows the equation of a line with slope -2 passing through (-32)?
30
How do you write the sum of -47 and 15 is -32 as an equation?
You can write the sum of -47 and 15 is -32 as an equation like this: -47 + 15 = -32. This equation states that when you add -47 and 15 together, the result is -32.
Find an equation of the line tangent to the curve defined by x^2+3xy+y^4=32 at the point (2,2)?
55
What is the equation for this answer n equals -32?
n=-32
