THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
find an equation of the line with shop -3 that conrains the point(-2,3)
y=-5/37x
It has no slope.
Points: (-1, -1) and (-3, 2) Slope: -3/2
Points: (-1, -1) and (-3, 2) Slope: -3/2
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
If you mean: 32-10x+7y = 0 then as a straight line equation it is 7y = 10x-32
If you mean points of: (-1, -4) and (3, 2) Slope: 3/2 Equation works out as: 2y = 3x-5
yes there is it would be 10!!
30
55
n=-32
Tc = (5/9)*(Tf-32) {Equation for Celsius} Tf = (9/5)*Tc+32 {Equation for Fahrenheit}
Without an equality sign and not knowing the plus or minus values of the given terms of the line which then can't be considered to be a straight line equation. In general for lines to be parallel to each other they will both have the same slope but different y intercepts.