Points: (12, 8) and (17, 16)
Slope: 8/5
Equation: 5y = 8x-32
y = -0.3x-1.5 in slope intercept form
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Y=_10.35x+126.125
The equation works out as: y = 5x+7
y = 7
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
Y= -3x + 8
It is y = 2.
If the line passes through (5, 2) and (5, 7), then the x value stays constant for those two points, and since it is a line, the x value stays constant for the whole line, so the equation of the line isx = 5
3
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
The equation for the given points is y = x+4 in slope intercept form
Answer this question…y = 2x + 6
Slope-intercept form