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16 + 20 + 14 = 50 = 12 + 14 +14 + 10
Here's one way to work that out. Let's call the numbers "a" and "b" We're told: a + b = 23 ab = 108 We can take one of those two, solve it for either a or b, substitute it into the other, and solve for the other variable using our new equation: a + b = 23 b = 23 - a ∴ a(23 - a) = 108 -a2 + 23a = 108 a2 - 23a + 108 = 0 a2 - 23a + (23/2)2 = (23/2)2 - 108 (a - 23/2)2 = 529/4 - 432/4 (a - 23/2)2 = 97/4 a - 23/2 = ± √(97/4) a = (23 ± √97) / 2 So the two numbers that meet this condition are (23 - √97) / 2 and (23 + √97) / 2
To find the mean (or average) you first add up the numbers you have. NOTHING 1.88
Using the identity, sin(X)+sin(Y) = 2*sin[(x+y)/2]*cos[(x-y)/2] the expression becomes {2*sin[(23A-7A)/2]*cos[(23A+7A)/2]}/{2*sin[(2A+14A)/2]*cos[(2A-14A)/2]} = {2*sin(8A)*cos(15A)}/{2*sin(8A)*cos(-6A)} = cos(15A)/cos(-6A)} = cos(15A)/cos(6A)} since cos(-x) = cos(x) When A = pi/21, 15A = 15*pi/21 and 6A = 6*pi/21 = pi - 15pi/21 Therefore, cos(6A) = - cos(15A) and hence the expression = -1.
Oh, dude, that's just a simple polynomial expression. The answer to 23a^2 minus 24a is like 23a^2 minus 24a. I mean, you could try to simplify it further, but like, why bother? It's already as simplified as it gets.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals".
16 + 20 + 14 = 50 = 12 + 14 +14 + 10
Here's one way to work that out. Let's call the numbers "a" and "b" We're told: a + b = 23 ab = 108 We can take one of those two, solve it for either a or b, substitute it into the other, and solve for the other variable using our new equation: a + b = 23 b = 23 - a ∴ a(23 - a) = 108 -a2 + 23a = 108 a2 - 23a + 108 = 0 a2 - 23a + (23/2)2 = (23/2)2 - 108 (a - 23/2)2 = 529/4 - 432/4 (a - 23/2)2 = 97/4 a - 23/2 = ± √(97/4) a = (23 ± √97) / 2 So the two numbers that meet this condition are (23 - √97) / 2 and (23 + √97) / 2
To find the mean (or average) you first add up the numbers you have. NOTHING 1.88
Using the identity, sin(X)+sin(Y) = 2*sin[(x+y)/2]*cos[(x-y)/2] the expression becomes {2*sin[(23A-7A)/2]*cos[(23A+7A)/2]}/{2*sin[(2A+14A)/2]*cos[(2A-14A)/2]} = {2*sin(8A)*cos(15A)}/{2*sin(8A)*cos(-6A)} = cos(15A)/cos(-6A)} = cos(15A)/cos(6A)} since cos(-x) = cos(x) When A = pi/21, 15A = 15*pi/21 and 6A = 6*pi/21 = pi - 15pi/21 Therefore, cos(6A) = - cos(15A) and hence the expression = -1.
The answer is 0 because at the end it is multiplied by 0
2+2+2+2+2+2+2+2+2+2+2+2+(2x0) =2+2+2+2+2+2+2+2+2+2+2+2+0 =24
16, think of it as 2 times 8.
56 (= 28 x 2)Copy pasted question redirected to numbered paragraphs for easy counting:2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2plus 2Total 56Equivalent to 28 * 2 = 56
2 + 2 + 2 + 2 + 2 + 2 + 2 -14 = 0
2 + 2 + 2 + 2 + 2 + 26 = 36