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I think you are asking about (-7x)^2 multiplied by x^2. The WikiAnswers notation does not allow all the characters so it is sometimes hard to tel If so, we first multiply the things in parentheses since that is what order of operations rules, PEMDAS, tells us. That would be 49x^2, now multiply that by x^2 and we have 49x^4
What else can I help you with?
What is 7x multiply by x?
The expression ( 7x ) multiplied by ( x ) can be simplified by applying the properties of multiplication. This results in ( 7x^2 ), which means 7 times the square of ( x ).
What does x equal if 7x square equals 7?
7xsquare = 7 x square = 1 x = +1 or -1
Factor 2x square - 7x plus 5?
(2x-5) (x-1)
How do you factorise 7x-x squared?
7x-x2 = x(7-x)
What are the zeros of the function square root of 7x plus 3?
To find the zeros of the function ( f(x) = \sqrt{7x + 3} ), we set the function equal to zero: ( \sqrt{7x + 3} = 0 ). Squaring both sides gives ( 7x + 3 = 0 ). Solving for ( x ) results in ( x = -\frac{3}{7} ). Therefore, the zero of the function is ( x = -\frac{3}{7} ).
What is 7x multiply by x?
The expression ( 7x ) multiplied by ( x ) can be simplified by applying the properties of multiplication. This results in ( 7x^2 ), which means 7 times the square of ( x ).
What does x equal if 7x square equals 7?
7xsquare = 7 x square = 1 x = +1 or -1
What is x-7x?
x - 7x = -6x
How do you solve 7x-2 equals x plus 4?
7x-4=x+2 7x=x+2+4 7x=x+6 7x-x=6 6x=6 X=1
Factor 2x square - 7x plus 5?
(2x-5) (x-1)
Solve X square root 2 equals 4 - 7x?
I understand your question to be this: x√2 = 4-7x So I would plus 7x to both sides to get this: x√2 + 7x = 4 Then take x out of the bracket to get this: x(√2 + 7) = 4 Finally divide both sides by (√2 + 7) to leave x on its on, and you should get something like this: x = 4/(√2 + 7)
What is 7x divided by 7x?
1
What is 7x minus x?
6x
How do you factorise 7x-x squared?
7x-x2 = x(7-x)
What are the zeros of the function square root of 7x plus 3?
To find the zeros of the function ( f(x) = \sqrt{7x + 3} ), we set the function equal to zero: ( \sqrt{7x + 3} = 0 ). Squaring both sides gives ( 7x + 3 = 0 ). Solving for ( x ) results in ( x = -\frac{3}{7} ). Therefore, the zero of the function is ( x = -\frac{3}{7} ).
What two numbers multiply together to equal -15 and add together to equal -7?
x + y = -7xy = -15y = -x - 7x(-x - 7) = -15-x^2 - 7x = -15 multiplying both sides by -1x^2 + 7x = 15 complete the square;(x^2 + 7x + 49/4) = 15 + 49/4(x + 7/2)^2 = 109/4(x + 7/2) = (plus & minus)square root of 109/41. x = -7/2 + (square root of 109)/22. x = -7/2 - (square root of 109)/2y = -x - 7y = -[-7/2 + (square root of 109)/2] - 7 = 7/2 - (square root of 109)/2 - 71. y = -7/2 - (square root of 109)/2 ory = -x - 7y = -[-7/2 - (square root of 109)/2] - 7 = 7/2 + (square root of 109)/2 - 72. y = -7/2 + (square root of 109)/2 Check it:
What is the answer for -7x-2?
Assume you mean -7x-2=0 solve for x -7x-2=0 -7x=2 -x=2/7 X=-2/7
