I think you are asking about (-7x)^2 multiplied by x^2. The WikiAnswers notation does not allow all the characters so it is sometimes hard to tel If so, we first multiply the things in parentheses since that is what order of operations rules, PEMDAS, tells us. That would be 49x^2, now multiply that by x^2 and we have 49x^4
7xsquare = 7 x square = 1 x = +1 or -1
x - 7x = -6x
7x-4=x+2 7x=x+2+4 7x=x+6 7x-x=6 6x=6 X=1
(2x-5) (x-1)
I understand your question to be this: x√2 = 4-7x So I would plus 7x to both sides to get this: x√2 + 7x = 4 Then take x out of the bracket to get this: x(√2 + 7) = 4 Finally divide both sides by (√2 + 7) to leave x on its on, and you should get something like this: x = 4/(√2 + 7)
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6x
7x-x2 = x(7-x)
x + y = -7xy = -15y = -x - 7x(-x - 7) = -15-x^2 - 7x = -15 multiplying both sides by -1x^2 + 7x = 15 complete the square;(x^2 + 7x + 49/4) = 15 + 49/4(x + 7/2)^2 = 109/4(x + 7/2) = (plus & minus)square root of 109/41. x = -7/2 + (square root of 109)/22. x = -7/2 - (square root of 109)/2y = -x - 7y = -[-7/2 + (square root of 109)/2] - 7 = 7/2 - (square root of 109)/2 - 71. y = -7/2 - (square root of 109)/2 ory = -x - 7y = -[-7/2 - (square root of 109)/2] - 7 = 7/2 + (square root of 109)/2 - 72. y = -7/2 + (square root of 109)/2 Check it:
Assume you mean -7x-2=0 solve for x -7x-2=0 -7x=2 -x=2/7 X=-2/7
In 7x+7, x is a variable.
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