3c - 12 = 14 + 5cSubtract 3c from each side:-12 = 14 + 2cSubtract 14 from each side:-26 = 2cDivide each side by 2:-13 = c
if you mean 6-5c=-29:c=7
5c+7=23 -7 -7 5c=16 /5 /5 c= 3 & 1/5 or 16/5 thats really easy algebra 1 homework isn't it
5c + 15= 30 - 15 -15 5c = 15 If your solving for just c..... 5c/5 = 30/5 c= 3 Hope this helps adding further your question is incomplete you must ask for the value of C, since its a arithmetic equation.
C=7. I'll show my work. 5c-8=27. 5c=35. C=7
When c = -3 then 4c + 5c - 2 = [4 x -3] + [5 x -3] - 2 = -12 +(-15) - 2 = -12 -15 -2 = -29
The value of c is 6
9
14c + c + 12 = 15c + 12 = 3(5c + 4)
3c - 12 = 14 + 5cSubtract 3c from each side:-12 = 14 + 2cSubtract 14 from each side:-26 = 2cDivide each side by 2:-13 = c
if you mean 6-5c=-29:c=7
5c+7=23 -7 -7 5c=16 /5 /5 c= 3 & 1/5 or 16/5 thats really easy algebra 1 homework isn't it
5c + 15= 30 - 15 -15 5c = 15 If your solving for just c..... 5c/5 = 30/5 c= 3 Hope this helps adding further your question is incomplete you must ask for the value of C, since its a arithmetic equation.
2(5c + 2d)(5c + 2d)
50 = sx3
C=7. I'll show my work. 5c-8=27. 5c=35. C=7
4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)