You didn't say 10+12i or 10-12i In the case of (10+12i), you would have a point in the xy plane @ x=10 and y=12 or (10,12) In the case of (10-12i), you would have a point in the xy plane @ x=10 and y=-12 or (10,-12) There are programs to "bend" photos with complex numbers. Refer to the LINK and Source below.
|5 + 12i| = +sqrt(52 + 122) = +sqrt(25 + 144) = +sqrt(169) = 13
12i=1f.
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)
The negative square root of -144 is -12i - that is -12 times the square root of minus 1, ie √-144 = 12√-1. The above is a complex number, which I suspect is not the answer you wanted; there is no real number that is the square root of a negative number If you wanted the negative square root of 144, then it is -12.
To find the complex conjugate of a number, change the sign in front of the imaginary part. Thus, the complex conjugate of 14 + 12i is simply 14 - 12i.
You didn't say 10+12i or 10-12i In the case of (10+12i), you would have a point in the xy plane @ x=10 and y=12 or (10,12) In the case of (10-12i), you would have a point in the xy plane @ x=10 and y=-12 or (10,-12) There are programs to "bend" photos with complex numbers. Refer to the LINK and Source below.
|5 + 12i| = +sqrt(52 + 122) = +sqrt(25 + 144) = +sqrt(169) = 13
12i=1f.
-12i(3-6i) = -36i + 72i² = -36i + 72 × -1 = -36i - 72 = -72 - 36i = -36(2 + i)
Assume we have the product of these terms. Multiply these terms altogether to get 12i². Make note that i = √-1, i² = -1, i³ = -i and i⁴ = 1. Then, 12i² = 12(-1) = -12. That is the answer to the question.
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Negative numbers have no real square roots.-144 has two square roots: 12i and -12i.
452.16 sq.inches
(7 + 3i) + (8 + 9i) = (7 + 8) + (3i + 9i) = (7 + 8) + (3 + 9)i = 15 + 12i Which can also be written as: 15 + 12i = 3(5 + 4i).
Not necessarily, take for example the equation x^2=5-12i. Then, 3-2i satisfies the equation. However, 3+2i does not because (3+2i)^2 = 5+12i.
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)