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Q: 12i in a f
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Find the complex conjugate of 14 plus 12i?

To find the complex conjugate of a number, change the sign in front of the imaginary part. Thus, the complex conjugate of 14 + 12i is simply 14 - 12i.


What is complex number of 10 12i?

You didn't say 10+12i or 10-12i In the case of (10+12i), you would have a point in the xy plane @ x=10 and y=12 or (10,12) In the case of (10-12i), you would have a point in the xy plane @ x=10 and y=-12 or (10,-12) There are programs to "bend" photos with complex numbers. Refer to the LINK and Source below.


What is the absolute value of 5 plus 12i?

|5 + 12i| = +sqrt(52 + 122) = +sqrt(25 + 144) = +sqrt(169) = 13


What is the formula of feet to inches conversion?

12i=1f.


What expression is equivalent to -12i(3-6i)?

-12i(3-6i) = -36i + 72i² = -36i + 72 × -1 = -36i - 72 = -72 - 36i = -36(2 + i)


How do you simplify 4i 3i?

Assume we have the product of these terms. Multiply these terms altogether to get 12i². Make note that i = √-1, i² = -1, i³ = -i and i⁴ = 1. Then, 12i² = 12(-1) = -12. That is the answer to the question.


how to solve this 4m-12i need show the solution?

16


What is the real number root of sqrt -144?

Negative numbers have no real square roots.-144 has two square roots: 12i and -12i.


What is the surface area of a cylinder with the radius of 6 inches and the height of 12i nches?

452.16 sq.inches


What is the sum of (7 plus 3i) plus (8 plus 9i)?

(7 + 3i) + (8 + 9i) = (7 + 8) + (3i + 9i) = (7 + 8) + (3 + 9)i = 15 + 12i Which can also be written as: 15 + 12i = 3(5 + 4i).


If 3 - 2i is a solution to a polynomial equation is the complex conjugate 3 plus 2i also a solution yes or no?

Not necessarily, take for example the equation x^2=5-12i. Then, 3-2i satisfies the equation. However, 3+2i does not because (3+2i)^2 = 5+12i.


What is the complex conjugate of a plus bi?

The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)