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Q: What is the answers to 5 - 7i 2 - 5i?
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Related questions

Write the complex number 2 - i divided by 5 plus i in the usual a plus bi form?

7


How do you solve 2 divided by 5i?

0.4


What is 1 divided by 2 plus 5i in the form a plus bi?

1/(2 + 5i) (multiply both the numerator and the denominator by 2 - 5i)= 1(2 - 5i)/(2 + 5i)(2 - 5i)= (2 - 5i)/(4 - 25i2) (substitute -1 for i2)= (2 - 5i)/(4 + 25)= (2 - 5i)/29= 2/29 - (5/29)i


What are the square roots of 25?

5, -5, 5i, -5i, 5i^2, and many others... If you're asking this question, chances are it is either 5 or negative 5.


What is the complex conjugate of -5 plus 7i?

-5 - 7i


What is the absolute value of 7i?

The absolute value is sqrt(72 + 12) = sqrt(49 + 1) = sqrt(50) or 5*sqrt(2) = 7.071 approx.


Complex conjugate of 5i?

0 + 5i Its complex conjugate is 0 - 5i


What is the reciprocal of 2-5i?

Let a + bi be the reciprocal. So (a + bi)(2 - 5i) = 1 (a + bi)(2 - 5i) = 2a - 5ai + 2bi + 5b = (2a + 5b) + (2b - 5a)i Therefore 2a + 5b = 1 and 2b - 5a = 0. Solving the simultaneous equations, we find that a = 2/29 and b = 5/29. So the reciprocal of 2 - 5i is 2/29 + 5i/29.


What are the cube roots of 1000i?

5√3 + 5i, -5√3 + 5i, -10i


How do you subtract imaginary numbers?

When adding and subtracting complex numbers, you can treat the "i" as any variable. For example, 5i + 3i = 8i, 5i -3i = 2i, etc.; (2 + 5i) - (3 - 3i) = (2 - 3) + (5 + 3)i = -1 + 8i.


What is the root of -25?

5i


Express this complex number in standard form i x sum of 5 plus 2i x sum of i-1?

i(2i+5)(i-1) [I hope I've interpreted this correctly - WikiAnswers does not make it easy to pose mathematical questions!] First of all, multiply out in ordinary fashion: i(2i+5)(i-1) = i(2i2 + 3i - 5) = 2i3 + 3i2 - 5i Now, i is defined in this way: i2 = -1 Multiplying both sides by i we get: i3 = -i Substitute this information into the expression: 2i3 + 3i2 - 5i = -2i - 3 - 5i = -3 - 7i Done. ---- As the exponent of i is raised, incidentally, you will observe a cycle like this: i, -1, -i, 1, i, -1...