not by complete number 60 = 6 x 10 54 = 6 x 9 59 = 6 x 9.83333 also, 59 is a prime number.
To solve this division problem, we need to find the number that, when divided into 40, gives a quotient of 6 with a remainder of 16. The formula to represent this situation is 40 = x * 6 + 16, where x is the number we are looking for. By rearranging the formula, we get x = (40 - 16) / 6, which simplifies to x = 24 / 6, and finally x = 4. Therefore, the number that, when divided into 40, gives a quotient of 6 with a remainder of 16 is 4.
16
If (x divided by 7) - 2 = 6, then x = 56 If x divided by (7 - 2) = 6, then x = 30
A quotient is the solution to a division sum. Therefore, x/6 = 16. If x/6 = 16 then x = 16 x 6 16 x 6 = 96 Therefore, x = 96.
59 x 6 = 354 59 x 10 = 590 Total: 944
100 ÷ 6 x 16 =266.67
6 divided by 3/8 is 6 x 8/3= 48/3 which is 16.
not by complete number 60 = 6 x 10 54 = 6 x 9 59 = 6 x 9.83333 also, 59 is a prime number.
To solve this division problem, we need to find the number that, when divided into 40, gives a quotient of 6 with a remainder of 16. The formula to represent this situation is 40 = x * 6 + 16, where x is the number we are looking for. By rearranging the formula, we get x = (40 - 16) / 6, which simplifies to x = 24 / 6, and finally x = 4. Therefore, the number that, when divided into 40, gives a quotient of 6 with a remainder of 16 is 4.
It is 119822294085.12
59/8 x 1/9 = 59/72
The answer will wind up being a pair of complex numbers. One way you can solve for x is by completing the square: 3x2 - x + 5 = 0 3x2 - x = -5 x2 - x/3 = -5/3 x2 - x/3 + 1/36 = -5/3 + 1/36 (x - 1/6)2 = (-60 + 1) / 36 (x - 1/6)2 = -59 / 36 x - 1/6 = ± √(-59 / 36) x - 1/6 = ± i√(59 / 36) x - 1/6 = ± i√59 / 6 x = 1/6 ± i√59 / 6 x = (1 ± i√59) / 6
59/8 x 1/9 = 59/72
16
If (x divided by 7) - 2 = 6, then x = 56 If x divided by (7 - 2) = 6, then x = 30
14 / 5/6 = 14 x 6 / 5 = 16.8, or 16 and four fifths.