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The answer will wind up being a pair of complex numbers. One way you can solve for x is by completing the square:

3x2 - x + 5 = 0

3x2 - x = -5

x2 - x/3 = -5/3

x2 - x/3 + 1/36 = -5/3 + 1/36

(x - 1/6)2 = (-60 + 1) / 36

(x - 1/6)2 = -59 / 36

x - 1/6 = ± √(-59 / 36)

x - 1/6 = ± i√(59 / 36)

x - 1/6 = ± i√59 / 6

x = 1/6 ± i√59 / 6

x = (1 ± i√59) / 6

Q: How do you find the solution for 3x squared minus x plus 5 equals zero?

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The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, âˆž).

y - 8 = x^2 + 12x + 36 y - 8 = (x + 6)^2 y = (x + 6)^2 + 8 or f(x) = (x + 6)^2 + 8 So -h = 6 so that h = -6, and k = 8

You don't. There's no question there, and nothing that needs solving. If it were equal to something, then we could find what number 'x' must be.

m2 - 8m = 0Factor the expression on the left:m (m - 8) = 0If either factor is zero, then the two sides are equal:m - 8 = 0m = 8m = 0

y = 5

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a=b=3.60555

Subtract the squared longer leg's squared length from the hypotenuse's square to obtain the squared shorter leg length. Then find the square root of that answer for your final answer. In other words: 53 squared minus 45 squared equals your squared answer.

The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, âˆž).

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I can't integrate a-x /x-3 ?