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How do you find the solution for 3x squared minus x plus 5 equals zero?
LissetteValle
The answer will wind up being a pair of complex numbers. One way you can solve for x is by completing the square:
3x2 - x + 5 = 0
3x2 - x = -5
x2 - x/3 = -5/3
x2 - x/3 + 1/36 = -5/3 + 1/36
(x - 1/6)2 = (-60 + 1) / 36
(x - 1/6)2 = -59 / 36
x - 1/6 = ± √(-59 / 36)
x - 1/6 = ± i√(59 / 36)
x - 1/6 = ± i√59 / 6
x = 1/6 ± i√59 / 6
x = (1 ± i√59) / 6
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