The weight (or mass) is irrelevant.
The period t = sqrt(2*pi*sqrt(l/g) where g is the acceleration due to gravity.
so t = 2*pi*sqrt(5/9.8) = 4.49 seconds.
Frequency = 1/period = 0.223 Hertz.
The period of a wave is defined as the time taken by a wave to complete one oscillation. While, the frequency of a wave is defined as the number of oscillations completed by a wave in one second.
Frequency = 1/period1/7.5 x 10-3 = 1331/3 Hz = 2/15 KHz
The relationship to be kept in mind is that the time period, which is the time take for one complete oscillation, is the reciprocal of frequency (the number of oscillations completed in one second). That is, T = 1/f where Period T, is measured in seconds Frequency f, is measured in Hertz. In your specific case, if f = 10 Hz, T = 0.1 s.
Period = 1 / frequency
Time period per oscillation=32/ 20=1.6 sec per oscillation.
The relationship between the torque of a pendulum and its oscillation frequency is that the torque affects the period of the pendulum, which in turn influences the oscillation frequency. A higher torque will result in a shorter period and a higher oscillation frequency, while a lower torque will lead to a longer period and a lower oscillation frequency.
The period of an oscillation can be calculated using the formula T = 1/f, where T is the period and f is the frequency of the oscillation. The frequency is the number of complete oscillations that occur in one second.
The time period of each oscillation is the time taken for one complete cycle of the oscillation to occur. It is typically denoted as T and is measured in seconds. The time period depends on the frequency of the oscillation, with the relationship T = 1/f, where f is the frequency of the oscillation in hertz.
The period of oscillation is the time taken for one complete oscillation. The frequency of oscillation, f, is the reciprocal of the period: f = 1 / T, where T is the period. In this case, the period T = 24.4 seconds / 50 oscillations = 0.488 seconds. Therefore, the frequency of oscillation is f = 1 / 0.488 seconds ≈ 2.05 Hz.
You can reduce the frequency of oscillation of a simple pendulum by increasing the length of the pendulum. This will increase the period of the pendulum, resulting in a lower frequency. Alternatively, you can decrease the mass of the pendulum bob, which will also reduce the frequency of oscillation.
The time period of oscillation is the time taken to complete one full cycle of oscillation, while frequency is the number of cycles per unit time. They are reciprocals of each other, with frequency being the inverse of the time period (frequency = 1/time period). This means that as the time period decreases, the frequency increases, and vice versa.
The reciprocal of frequency is the time period of the wave
The inverse of frequency.
T=1/f .5=1/f f=2
When the product of frequency and time period is equal to 1, it indicates that the oscillation completes one full cycle in one second, which is the definition of the unit hertz (Hz) for frequency.
The period of an electromagnetic wave is the reciprocal of the frequency. The wavelength is inversely proportional to the frequency.
The period of a simple pendulum is the time it takes for one full oscillation (swing) back and forth. To find the period, you can use the formula: Period = 1 / Frequency. So, if the frequency is 20 Hz, the period would be 1/20 = 0.05 seconds.